solution
stringlengths
10
159k
difficulty
int64
0
3.5k
language
stringclasses
2 values
#include <bits/stdc++.h> using namespace std; int n, x, y, x2, y2; int main() { cin >> n >> x >> y >> x2 >> y2; if (abs(x - x2) == n) cout << n + min(2 * n - (y + y2), y + y2); else if (abs(y - y2) == n) cout << n + min(2 * n - (x + x2), x + x2); else cout << abs(x - x2) + abs(y - y2); return 0; }
1,300
CPP
import sys input = sys.stdin.readline I = lambda : list(map(int,input().split())) t,=I() for _ in range(t): a,b,x,y,n=I() o=(a+b-x-y) tt=max(0,o-n) fx=min(x+tt,a) tt-=(fx-x) fb=y if tt: fb=min(y+tt,b) an=fx*fb x,y=y,x;a,b=b,a tt=max(0,o-n) fx=min(x+tt,a) tt-=(fx-x) fb=y if tt: fb=min(y+tt,b) an=min(fx*fb,an) print(an)
1,100
PYTHON3
song = str(input()) def wards_of_song(song): song = song.split('WUB') list_of_song = [] for i in song: if i != '': list_of_song += [i] return " ".join( list_of_song) print( wards_of_song(song))
900
PYTHON3
'''input aBAcAba ''' string = input().lower() li = [] vowels = ['a', 'e', 'i', 'o', 'u', 'y'] for i in string: if i in vowels: continue else: li.append('.') li.append(i) print(''.join(li))
1,000
PYTHON3
s=input().lower() v='aeiouy' for i in s: if i not in v: print('.'+str(i),end='')
1,000
PYTHON3
def run(): n = int(input()) nums = [int(i) for i in input().split()] nums.sort() for i in range(1, n): if nums[i] > (nums[i-1] + 1): print("NO") return print("YES") return t = int(input()) for i in range(t): run()
800
PYTHON3
#include <bits/stdc++.h> using namespace std; template <typename C> void MA(C& a, C b) { if (a < b) a = b; } template <typename C> void MI(C& a, C b) { if (a > b) a = b; } const int P = 1e9 + 7; int n, k; bool isl(int a) { if (a == 0) return 1; return (a % 10 == 4 || a % 10 == 7) && isl(a / 10); } int w[102001]; int iw = -1; map<int, int> m; long long pot(long long a, long long w) { long long r = 1; while (w) { if (w & 1) { r *= a; r %= P; } w /= 2; a *= a; a %= P; } return r; } long long sil[102001], odw[102001]; long long po(int a, int b) { if (a < b || b < 0) return 0; return sil[a] * odw[b] % P * odw[a - b] % P; } int main() { scanf("%d%d", &n, &k); sil[0] = 1; for (int i = 0; i < n + 1; i++) { sil[i + 1] = sil[i] * (i + 1) % P; } for (int i = 0; i < n + 1; i++) { odw[i] = pot(sil[i], P - 2); } for (int i = 0; i < n; i++) { int pom; scanf("%d", &pom); if (isl(pom)) { auto x = m.find(pom); if (x != m.end()) { w[x->second]++; } else { iw++; m[pom] = iw; w[iw] = 1; } } else { iw++; w[iw] = 1; } } iw++; vector<int> a; a.push_back(1); int il1 = 0; for (int i = 0; i < iw; i++) { if (w[i] == 1) { il1++; } else { a.push_back(0); vector<int> b; b.push_back(1); for (int ii = 1; ii < a.size(); ii++) { b.push_back((a[ii] + a[ii - 1] * 1ll * w[i]) % P); } swap(a, b); } } long long wyn = 0; while (a.size() < k + 1) a.push_back(0); for (int i = 0; i < k + 1; i++) { wyn += po(il1, i) * a[k - i] % P; } cout << wyn % P << "\n"; }
2,100
CPP
#include <bits/stdc++.h> using namespace std; int T, n, nxt[102][26], lst[26], tot[26]; char s[102], t[102]; int main() { ios::sync_with_stdio(false); cin >> T; while (T--) { int ans = 0, flg = 0; memset(tot, 0, sizeof(tot)); cin >> n >> s + 1 >> t + 1; for (int i = 1; i <= n; ++i) { s[i] -= 'a', t[i] -= 'a'; ++tot[s[i]], --tot[t[i]]; } for (int i = 0; i < 26; ++i) { if (tot[i] != 0) flg = 1; } if (flg) ans = n + 1; else { memset(lst, -1, sizeof(lst)); for (int i = n; i >= 0; --i) { for (int j = 0; j < 26; ++j) nxt[i][j] = lst[j]; lst[s[i]] = i; } for (int i = 1; i <= n; ++i) { int w = 0, cnt = 0; for (int j = i; j <= n; ++j) { w = nxt[w][t[j]]; if (w < 0) break; ++cnt; } ans = max(ans, cnt); } } cout << n - ans << endl; } return 0; }
2,200
CPP