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1 | Making sense of principal component analysis, eigenvectors & eigenvalues | Imagine a big family dinner where everybody starts asking you about PCA. First, you explain it to your great-grandmother; then to your grandmother; then to your mother; then to your spouse; finally, to your daughter (a mathematician). Each time the next person is less of a layman. Here is how the conversation might go.
Great-grandmother: I heard you are studying "Pee-See-Ay". I wonder what that is...
You: Ah, it's just a method of summarizing some data. Look, we have some wine bottles standing here on the table. We can describe each wine by its colour, how strong it is, how old it is, and so on.
Visualization originally found here.
We can compose a whole list of different characteristics of each wine in our cellar. But many of them will measure related properties and so will be redundant. If so, we should be able to summarize each wine with fewer characteristics! This is what PCA does.
Grandmother: This is interesting! So this PCA thing checks what characteristics are redundant and discards them?
You: Excellent question, granny! No, PCA is not selecting some characteristics and discarding the others. Instead, it constructs some new characteristics that turn out to summarize our list of wines well. Of course, these new characteristics are constructed using the old ones; for example, a new characteristic might be computed as wine age minus wine acidity level or some other combination (we call them linear combinations).
In fact, PCA finds the best possible characteristics, the ones that summarize the list of wines as well as only possible (among all conceivable linear combinations). This is why it is so useful.
Mother: Hmmm, this certainly sounds good, but I am not sure I understand. What do you actually mean when you say that these new PCA characteristics "summarize" the list of wines?
You: I guess I can give two different answers to this question. The first answer is that you are looking for some wine properties (characteristics) that strongly differ across wines. Indeed, imagine that you come up with a property that is the same for most of the wines - like the stillness of wine after being poured. This would not be very useful, would it? Wines are very different, but your new property makes them all look the same! This would certainly be a bad summary. Instead, PCA looks for properties that show as much variation across wines as possible.
The second answer is that you look for the properties that would allow you to predict, or "reconstruct", the original wine characteristics. Again, imagine that you come up with a property that has no relation to the original characteristics - like the shape of a wine bottle; if you use only this new property, there is no way you could reconstruct the original ones! This, again, would be a bad summary. So PCA looks for properties that allow reconstructing the original characteristics as well as possible.
Surprisingly, it turns out that these two aims are equivalent and so PCA can kill two birds with one stone.
Spouse: But darling, these two "goals" of PCA sound so different! Why would they be equivalent?
You: Hmmm. Perhaps I should make a little drawing (takes a napkin and starts scribbling). Let us pick two wine characteristics, perhaps wine darkness and alcohol content -- I don't know if they are correlated, but let's imagine that they are. Here is what a scatter plot of different wines could look like:
Each dot in this "wine cloud" shows one particular wine. You see that the two properties ($x$ and $y$ on this figure) are correlated. A new property can be constructed by drawing a line through the centre of this wine cloud and projecting all points onto this line. This new property will be given by a linear combination $w_1 x + w_2 y$, where each line corresponds to some particular values of $w_1$ and $w_2$.
Now, look here very carefully -- here is what these projections look like for different lines (red dots are projections of the blue dots):
As I said before, PCA will find the "best" line according to two different criteria of what is the "best". First, the variation of values along this line should be maximal. Pay attention to how the "spread" (we call it "variance") of the red dots changes while the line rotates; can you see when it reaches maximum? Second, if we reconstruct the original two characteristics (position of a blue dot) from the new one (position of a red dot), the reconstruction error will be given by the length of the connecting red line. Observe how the length of these red lines changes while the line rotates; can you see when the total length reaches minimum?
If you stare at this animation for some time, you will notice that "the maximum variance" and "the minimum error" are reached at the same time, namely when the line points to the magenta ticks I marked on both sides of the wine cloud. This line corresponds to the new wine property that will be constructed by PCA.
By the way, PCA stands for "principal component analysis", and this new property is called "first principal component". And instead of saying "property" or "characteristic", we usually say "feature" or "variable".
Daughter: Very nice, papa! I think I can see why the two goals yield the same result: it is essentially because of the Pythagoras theorem, isn't it? Anyway, I heard that PCA is somehow related to eigenvectors and eigenvalues; where are they in this picture?
You: Brilliant observation. Mathematically, the spread of the red dots is measured as the average squared distance from the centre of the wine cloud to each red dot; as you know, it is called the variance. On the other hand, the total reconstruction error is measured as the average squared length of the corresponding red lines. But as the angle between red lines and the black line is always $90^\circ$, the sum of these two quantities is equal to the average squared distance between the centre of the wine cloud and each blue dot; this is precisely Pythagoras theorem. Of course, this average distance does not depend on the orientation of the black line, so the higher the variance, the lower the error (because their sum is constant). This hand-wavy argument can be made precise (see here).
By the way, you can imagine that the black line is a solid rod, and each red line is a spring. The energy of the spring is proportional to its squared length (this is known in physics as Hooke's law), so the rod will orient itself such as to minimize the sum of these squared distances. I made a simulation of what it will look like in the presence of some viscous friction:
Regarding eigenvectors and eigenvalues. You know what a covariance matrix is; in my example it is a $2\times 2$ matrix that is given by $$\begin{pmatrix}1.07 &0.63\\0.63 & 0.64\end{pmatrix}.$$ What this means is that the variance of the $x$ variable is $1.07$, the variance of the $y$ variable is $0.64$, and the covariance between them is $0.63$. As it is a square symmetric matrix, it can be diagonalized by choosing a new orthogonal coordinate system, given by its eigenvectors (incidentally, this is called spectral theorem); corresponding eigenvalues will then be located on the diagonal. In this new coordinate system, the covariance matrix is diagonal and looks like that: $$\begin{pmatrix}1.52 &0\\0 & 0.19\end{pmatrix},$$ meaning that the correlation between points is now zero. It becomes clear that the variance of any projection will be given by a weighted average of the eigenvalues (I am only sketching the intuition here). Consequently, the maximum possible variance ($1.52$) will be achieved if we simply take the projection on the first coordinate axis. It follows that the direction of the first principal component is given by the first eigenvector of the covariance matrix. (More details here.)
You can see this on the rotating figure as well: there is a gray line there orthogonal to the black one; together, they form a rotating coordinate frame. Try to notice when the blue dots become uncorrelated in this rotating frame. The answer, again, is that it happens precisely when the black line points at the magenta ticks. Now I can tell you how I found them (the magenta ticks): they mark the direction of the first eigenvector of the covariance matrix, which in this case is equal to $(0.81, 0.58)$.
Per popular request, I shared the Matlab code to produce the above animations. | Making sense of principal component analysis, eigenvectors & eigenvalues | Imagine a big family dinner where everybody starts asking you about PCA. First, you explain it to your great-grandmother; then to your grandmother; then to your mother; then to your spouse; finally, t | Making sense of principal component analysis, eigenvectors & eigenvalues
Imagine a big family dinner where everybody starts asking you about PCA. First, you explain it to your great-grandmother; then to your grandmother; then to your mother; then to your spouse; finally, to your daughter (a mathematician). Each time the next person is less of a layman. Here is how the conversation might go.
Great-grandmother: I heard you are studying "Pee-See-Ay". I wonder what that is...
You: Ah, it's just a method of summarizing some data. Look, we have some wine bottles standing here on the table. We can describe each wine by its colour, how strong it is, how old it is, and so on.
Visualization originally found here.
We can compose a whole list of different characteristics of each wine in our cellar. But many of them will measure related properties and so will be redundant. If so, we should be able to summarize each wine with fewer characteristics! This is what PCA does.
Grandmother: This is interesting! So this PCA thing checks what characteristics are redundant and discards them?
You: Excellent question, granny! No, PCA is not selecting some characteristics and discarding the others. Instead, it constructs some new characteristics that turn out to summarize our list of wines well. Of course, these new characteristics are constructed using the old ones; for example, a new characteristic might be computed as wine age minus wine acidity level or some other combination (we call them linear combinations).
In fact, PCA finds the best possible characteristics, the ones that summarize the list of wines as well as only possible (among all conceivable linear combinations). This is why it is so useful.
Mother: Hmmm, this certainly sounds good, but I am not sure I understand. What do you actually mean when you say that these new PCA characteristics "summarize" the list of wines?
You: I guess I can give two different answers to this question. The first answer is that you are looking for some wine properties (characteristics) that strongly differ across wines. Indeed, imagine that you come up with a property that is the same for most of the wines - like the stillness of wine after being poured. This would not be very useful, would it? Wines are very different, but your new property makes them all look the same! This would certainly be a bad summary. Instead, PCA looks for properties that show as much variation across wines as possible.
The second answer is that you look for the properties that would allow you to predict, or "reconstruct", the original wine characteristics. Again, imagine that you come up with a property that has no relation to the original characteristics - like the shape of a wine bottle; if you use only this new property, there is no way you could reconstruct the original ones! This, again, would be a bad summary. So PCA looks for properties that allow reconstructing the original characteristics as well as possible.
Surprisingly, it turns out that these two aims are equivalent and so PCA can kill two birds with one stone.
Spouse: But darling, these two "goals" of PCA sound so different! Why would they be equivalent?
You: Hmmm. Perhaps I should make a little drawing (takes a napkin and starts scribbling). Let us pick two wine characteristics, perhaps wine darkness and alcohol content -- I don't know if they are correlated, but let's imagine that they are. Here is what a scatter plot of different wines could look like:
Each dot in this "wine cloud" shows one particular wine. You see that the two properties ($x$ and $y$ on this figure) are correlated. A new property can be constructed by drawing a line through the centre of this wine cloud and projecting all points onto this line. This new property will be given by a linear combination $w_1 x + w_2 y$, where each line corresponds to some particular values of $w_1$ and $w_2$.
Now, look here very carefully -- here is what these projections look like for different lines (red dots are projections of the blue dots):
As I said before, PCA will find the "best" line according to two different criteria of what is the "best". First, the variation of values along this line should be maximal. Pay attention to how the "spread" (we call it "variance") of the red dots changes while the line rotates; can you see when it reaches maximum? Second, if we reconstruct the original two characteristics (position of a blue dot) from the new one (position of a red dot), the reconstruction error will be given by the length of the connecting red line. Observe how the length of these red lines changes while the line rotates; can you see when the total length reaches minimum?
If you stare at this animation for some time, you will notice that "the maximum variance" and "the minimum error" are reached at the same time, namely when the line points to the magenta ticks I marked on both sides of the wine cloud. This line corresponds to the new wine property that will be constructed by PCA.
By the way, PCA stands for "principal component analysis", and this new property is called "first principal component". And instead of saying "property" or "characteristic", we usually say "feature" or "variable".
Daughter: Very nice, papa! I think I can see why the two goals yield the same result: it is essentially because of the Pythagoras theorem, isn't it? Anyway, I heard that PCA is somehow related to eigenvectors and eigenvalues; where are they in this picture?
You: Brilliant observation. Mathematically, the spread of the red dots is measured as the average squared distance from the centre of the wine cloud to each red dot; as you know, it is called the variance. On the other hand, the total reconstruction error is measured as the average squared length of the corresponding red lines. But as the angle between red lines and the black line is always $90^\circ$, the sum of these two quantities is equal to the average squared distance between the centre of the wine cloud and each blue dot; this is precisely Pythagoras theorem. Of course, this average distance does not depend on the orientation of the black line, so the higher the variance, the lower the error (because their sum is constant). This hand-wavy argument can be made precise (see here).
By the way, you can imagine that the black line is a solid rod, and each red line is a spring. The energy of the spring is proportional to its squared length (this is known in physics as Hooke's law), so the rod will orient itself such as to minimize the sum of these squared distances. I made a simulation of what it will look like in the presence of some viscous friction:
Regarding eigenvectors and eigenvalues. You know what a covariance matrix is; in my example it is a $2\times 2$ matrix that is given by $$\begin{pmatrix}1.07 &0.63\\0.63 & 0.64\end{pmatrix}.$$ What this means is that the variance of the $x$ variable is $1.07$, the variance of the $y$ variable is $0.64$, and the covariance between them is $0.63$. As it is a square symmetric matrix, it can be diagonalized by choosing a new orthogonal coordinate system, given by its eigenvectors (incidentally, this is called spectral theorem); corresponding eigenvalues will then be located on the diagonal. In this new coordinate system, the covariance matrix is diagonal and looks like that: $$\begin{pmatrix}1.52 &0\\0 & 0.19\end{pmatrix},$$ meaning that the correlation between points is now zero. It becomes clear that the variance of any projection will be given by a weighted average of the eigenvalues (I am only sketching the intuition here). Consequently, the maximum possible variance ($1.52$) will be achieved if we simply take the projection on the first coordinate axis. It follows that the direction of the first principal component is given by the first eigenvector of the covariance matrix. (More details here.)
You can see this on the rotating figure as well: there is a gray line there orthogonal to the black one; together, they form a rotating coordinate frame. Try to notice when the blue dots become uncorrelated in this rotating frame. The answer, again, is that it happens precisely when the black line points at the magenta ticks. Now I can tell you how I found them (the magenta ticks): they mark the direction of the first eigenvector of the covariance matrix, which in this case is equal to $(0.81, 0.58)$.
Per popular request, I shared the Matlab code to produce the above animations. | Making sense of principal component analysis, eigenvectors & eigenvalues
Imagine a big family dinner where everybody starts asking you about PCA. First, you explain it to your great-grandmother; then to your grandmother; then to your mother; then to your spouse; finally, t |
2 | Making sense of principal component analysis, eigenvectors & eigenvalues | The manuscript "A tutorial on Principal Components Analysis" by Lindsay I Smith really helped me grok PCA. I think it's still too complex for explaining to your grandmother, but it's not bad. You should skip first few bits on calculating eigens, etc. Jump down to the example in chapter 3 and look at the graphs.
I have some examples where I worked through some toy examples so I could understand PCA vs. OLS linear regression. I'll try to dig those up and post them as well.
edit:
You didn't really ask about the difference between Ordinary Least Squares (OLS) and PCA but since I dug up my notes I did a blog post about it. The very short version is OLS of y ~ x minimizes error perpendicular to the independent axis like this (yellow lines are examples of two errors):
If you were to regress x ~ y (as opposed to y ~ x in the first example) it would minimize error like this:
and PCA effectively minimizes error orthogonal to the model itself, like so:
More importantly, as others have said, in a situation where you have a WHOLE BUNCH of independent variables, PCA helps you figure out which linear combinations of these variables matter the most. The examples above just help visualize what the first principal component looks like in a really simple case.
In my blog post I have the R code for creating the above graphs and for calculating the first principal component. It might be worth playing with to build your intuition around PCA. I tend to not really own something until I write code that reproduces it. | Making sense of principal component analysis, eigenvectors & eigenvalues | The manuscript "A tutorial on Principal Components Analysis" by Lindsay I Smith really helped me grok PCA. I think it's still too complex for explaining to your grandmother, but it's not bad. You shou | Making sense of principal component analysis, eigenvectors & eigenvalues
The manuscript "A tutorial on Principal Components Analysis" by Lindsay I Smith really helped me grok PCA. I think it's still too complex for explaining to your grandmother, but it's not bad. You should skip first few bits on calculating eigens, etc. Jump down to the example in chapter 3 and look at the graphs.
I have some examples where I worked through some toy examples so I could understand PCA vs. OLS linear regression. I'll try to dig those up and post them as well.
edit:
You didn't really ask about the difference between Ordinary Least Squares (OLS) and PCA but since I dug up my notes I did a blog post about it. The very short version is OLS of y ~ x minimizes error perpendicular to the independent axis like this (yellow lines are examples of two errors):
If you were to regress x ~ y (as opposed to y ~ x in the first example) it would minimize error like this:
and PCA effectively minimizes error orthogonal to the model itself, like so:
More importantly, as others have said, in a situation where you have a WHOLE BUNCH of independent variables, PCA helps you figure out which linear combinations of these variables matter the most. The examples above just help visualize what the first principal component looks like in a really simple case.
In my blog post I have the R code for creating the above graphs and for calculating the first principal component. It might be worth playing with to build your intuition around PCA. I tend to not really own something until I write code that reproduces it. | Making sense of principal component analysis, eigenvectors & eigenvalues
The manuscript "A tutorial on Principal Components Analysis" by Lindsay I Smith really helped me grok PCA. I think it's still too complex for explaining to your grandmother, but it's not bad. You shou |
3 | Making sense of principal component analysis, eigenvectors & eigenvalues | Let's do (2) first. PCA fits an ellipsoid to the data. An ellipsoid is a multidimensional generalization of distorted spherical shapes like cigars, pancakes, and eggs. These are all neatly described by the directions and lengths of their principal (semi-)axes, such as the axis of the cigar or egg or the plane of the pancake. No matter how the ellipsoid is turned, the eigenvectors point in those principal directions and the eigenvalues give you the lengths. The smallest eigenvalues correspond to the thinnest directions having the least variation, so ignoring them (which collapses them flat) loses relatively little information: that's PCA.
(1) Apart from simplification (above), we have needs for pithy description, visualization, and insight. Being able to reduce dimensions is a good thing: it makes it easier to describe the data and, if we're lucky to reduce them to three or less, lets us draw a picture. Sometimes we can even find useful ways to interpret the combinations of data represented by the coordinates in the picture, which can afford insight into the joint behavior of the variables.
The figure shows some clouds of $200$ points each, along with ellipsoids containing 50% of each cloud and axes aligned with the principal directions. In the first row the clouds have essentially one principal component, comprising 95% of all the variance: these are the cigar shapes. In the second row the clouds have essentially two principal components, one about twice the size of the other, together comprising 95% of all the variance: these are the pancake shapes. In the third row all three principal components are sizable: these are the egg shapes.
Any 3D point cloud that is "coherent" in the sense of not exhibiting clusters or tendrils or outliers will look like one of these. Any 3D point cloud at all--provided not all the points are coincident--can be described by one of these figures as an initial point of departure for identifying further clustering or patterning.
The intuition you develop from contemplating such configurations can be applied to higher dimensions, even though it is difficult or impossible to visualize those dimensions. | Making sense of principal component analysis, eigenvectors & eigenvalues | Let's do (2) first. PCA fits an ellipsoid to the data. An ellipsoid is a multidimensional generalization of distorted spherical shapes like cigars, pancakes, and eggs. These are all neatly describe | Making sense of principal component analysis, eigenvectors & eigenvalues
Let's do (2) first. PCA fits an ellipsoid to the data. An ellipsoid is a multidimensional generalization of distorted spherical shapes like cigars, pancakes, and eggs. These are all neatly described by the directions and lengths of their principal (semi-)axes, such as the axis of the cigar or egg or the plane of the pancake. No matter how the ellipsoid is turned, the eigenvectors point in those principal directions and the eigenvalues give you the lengths. The smallest eigenvalues correspond to the thinnest directions having the least variation, so ignoring them (which collapses them flat) loses relatively little information: that's PCA.
(1) Apart from simplification (above), we have needs for pithy description, visualization, and insight. Being able to reduce dimensions is a good thing: it makes it easier to describe the data and, if we're lucky to reduce them to three or less, lets us draw a picture. Sometimes we can even find useful ways to interpret the combinations of data represented by the coordinates in the picture, which can afford insight into the joint behavior of the variables.
The figure shows some clouds of $200$ points each, along with ellipsoids containing 50% of each cloud and axes aligned with the principal directions. In the first row the clouds have essentially one principal component, comprising 95% of all the variance: these are the cigar shapes. In the second row the clouds have essentially two principal components, one about twice the size of the other, together comprising 95% of all the variance: these are the pancake shapes. In the third row all three principal components are sizable: these are the egg shapes.
Any 3D point cloud that is "coherent" in the sense of not exhibiting clusters or tendrils or outliers will look like one of these. Any 3D point cloud at all--provided not all the points are coincident--can be described by one of these figures as an initial point of departure for identifying further clustering or patterning.
The intuition you develop from contemplating such configurations can be applied to higher dimensions, even though it is difficult or impossible to visualize those dimensions. | Making sense of principal component analysis, eigenvectors & eigenvalues
Let's do (2) first. PCA fits an ellipsoid to the data. An ellipsoid is a multidimensional generalization of distorted spherical shapes like cigars, pancakes, and eggs. These are all neatly describe |
4 | Making sense of principal component analysis, eigenvectors & eigenvalues | Hmm, here goes for a completely non-mathematical take on PCA...
Imagine you have just opened a cider shop. You have 50 varieties of cider and you want to work out how to allocate them onto shelves, so that similar-tasting ciders are put on the same shelf. There are lots of different tastes and textures in cider - sweetness, tartness, bitterness, yeastiness, fruitiness, clarity, fizziness etc etc. So what you need to do to put the bottles into categories is answer two questions:
1) What qualities are most important for identifying groups of ciders? e.g. does classifying based on sweetness make it easier to cluster your ciders into similar-tasting groups than classifying based on fruitiness?
2) Can we reduce our list of variables by combining some of them? e.g. is there actually a variable that is some combination of "yeastiness and clarity and fizziness" and which makes a really good scale for classifying varieties?
This is essentially what PCA does. Principal components are variables that usefully explain variation in a data set - in this case, that usefully differentiate between groups. Each principal component is one of your original explanatory variables, or a combination of some of your original explanatory variables. | Making sense of principal component analysis, eigenvectors & eigenvalues | Hmm, here goes for a completely non-mathematical take on PCA...
Imagine you have just opened a cider shop. You have 50 varieties of cider and you want to work out how to allocate them onto shelves, s | Making sense of principal component analysis, eigenvectors & eigenvalues
Hmm, here goes for a completely non-mathematical take on PCA...
Imagine you have just opened a cider shop. You have 50 varieties of cider and you want to work out how to allocate them onto shelves, so that similar-tasting ciders are put on the same shelf. There are lots of different tastes and textures in cider - sweetness, tartness, bitterness, yeastiness, fruitiness, clarity, fizziness etc etc. So what you need to do to put the bottles into categories is answer two questions:
1) What qualities are most important for identifying groups of ciders? e.g. does classifying based on sweetness make it easier to cluster your ciders into similar-tasting groups than classifying based on fruitiness?
2) Can we reduce our list of variables by combining some of them? e.g. is there actually a variable that is some combination of "yeastiness and clarity and fizziness" and which makes a really good scale for classifying varieties?
This is essentially what PCA does. Principal components are variables that usefully explain variation in a data set - in this case, that usefully differentiate between groups. Each principal component is one of your original explanatory variables, or a combination of some of your original explanatory variables. | Making sense of principal component analysis, eigenvectors & eigenvalues
Hmm, here goes for a completely non-mathematical take on PCA...
Imagine you have just opened a cider shop. You have 50 varieties of cider and you want to work out how to allocate them onto shelves, s |
5 | Making sense of principal component analysis, eigenvectors & eigenvalues | I'd answer in "layman's terms" by saying that PCA aims to fit straight lines to the data points (everyone knows what a straight line is). We call these straight lines "principal components". There are as many principal components as there are variables. The first principal component is the best straight line you can fit to the data. The second principal component is the best straight line you can fit to the errors from the first principal component. The third principal component is the best straight line you can fit to the errors from the first and second principal components, etc., etc.
If someone asks what you mean by "best" or "errors", then this tells you they are not a "layman", so can go into a bit more technical details such as perpendicular errors, don't know where the error is in x- or y- direction, more than 2 or 3 dimensions, etc. Further if you avoid making reference to OLS regression (which the "layman" probably won't understand either) the explanation is easier.
The eigenvectors and eigenvalues are not needed concepts per se, rather they happened to be mathematical concepts that already existed. When you solve the mathematical problem of PCA, it ends up being equivalent to finding the eigenvalues and eigenvectors of the covariance matrix. | Making sense of principal component analysis, eigenvectors & eigenvalues | I'd answer in "layman's terms" by saying that PCA aims to fit straight lines to the data points (everyone knows what a straight line is). We call these straight lines "principal components". There a | Making sense of principal component analysis, eigenvectors & eigenvalues
I'd answer in "layman's terms" by saying that PCA aims to fit straight lines to the data points (everyone knows what a straight line is). We call these straight lines "principal components". There are as many principal components as there are variables. The first principal component is the best straight line you can fit to the data. The second principal component is the best straight line you can fit to the errors from the first principal component. The third principal component is the best straight line you can fit to the errors from the first and second principal components, etc., etc.
If someone asks what you mean by "best" or "errors", then this tells you they are not a "layman", so can go into a bit more technical details such as perpendicular errors, don't know where the error is in x- or y- direction, more than 2 or 3 dimensions, etc. Further if you avoid making reference to OLS regression (which the "layman" probably won't understand either) the explanation is easier.
The eigenvectors and eigenvalues are not needed concepts per se, rather they happened to be mathematical concepts that already existed. When you solve the mathematical problem of PCA, it ends up being equivalent to finding the eigenvalues and eigenvectors of the covariance matrix. | Making sense of principal component analysis, eigenvectors & eigenvalues
I'd answer in "layman's terms" by saying that PCA aims to fit straight lines to the data points (everyone knows what a straight line is). We call these straight lines "principal components". There a |
6 | Making sense of principal component analysis, eigenvectors & eigenvalues | I can give you my own explanation/proof of the PCA, which I think is really simple and elegant, and doesn't require anything except basic knowledge of linear algebra. It came out pretty lengthy, because I wanted to write in simple accessible language.
Suppose we have some $M$ samples of data from an $n$-dimensional space. Now we want to project this data on a few lines in the $n$-dimensional space, in a way that retains as much variance as possible (that means, the variance of the projected data should be as big compared to the variance of original data as possible).
Now, let's observe that if we translate (move) all the points by some vector $\beta$, the variance will remain the same, since moving all points by $\beta$ will move their arithmetic mean by $\beta$ as well, and variance is linearly proportional to $\sum_{i=1}^M \|x_i - \mu\|^2$. Hence we translate all the points by $-\mu$, so that their arithmetic mean becomes $0$, for computational comfort. Let's denote the translated points as $x_i' = x_i - \mu$. Let's also observe, that the variance can be now expressed simply as $\sum_{i=1}^M \|x_i'\|^2$.
Now the choice of the line. We can describe any line as set of points that satisfy the equation $x = \alpha v + w$, for some vectors $v,w$. Note that if we move the line by some vector $\gamma$ orthogonal to $v$, then all the projections on the line will also be moved by $\gamma$, hence the mean of the projections will be moved by $\gamma$, hence the variance of the projections will remain unchanged. That means we can move the line parallel to itself, and not change the variance of projections on this line. Again for convenience purposes let's limit ourselves to only the lines passing through the zero point (this means lines described by $x = \alpha v$).
Alright, now suppose we have a vector $v$ that describes the direction of a line that is a possible candidate for the line we search for. We need to calculate variance of the projections on the line $\alpha v$. What we will need are projection points and their mean. From linear algebra we know that in this simple case the projection of $x_i'$ on $\alpha v$ is $\langle x_i, v\rangle/\|v\|_2$. Let's from now on limit ourselves to only unit vectors $v$. That means we can write the length of projection of point $x_i'$ on $v$ simply as $\langle x_i', v\rangle$.
In some of the previous answers someone said that PCA minimizes the sum of squares of distances from the chosen line. We can now see it's true, because sum of squares of projections plus sum of squares of distances from the chosen line is equal to the sum of squares of distances from point $0$. By maximizing the sum of squares of projections, we minimize the sum of squares of distances and vice versa, but this was just a thoughtful digression, back to the proof now.
As for the mean of the projections, let's observe that $v$ is part of some orthogonal basis of our space, and that if we project our data points on every vector of that basis, their sum will cancel out (it's like that because projecting on the vectors from the basis is like writing the data points in the new orthogonal basis). So the sum of all the projections on the vector $v$ (let's call the sum $S_v$) and the sum of projections on other vectors from the basis (let's call it $S_o$) is 0, because it's the mean of the data points. But $S_v$ is orthogonal to $S_o$! That means $S_o = S_v = 0$.
So the mean of our projections is $0$. Well, that's convenient, because that means the variance is just the sum of squares of lengths of projections, or in symbols $$\sum_{i=1}^M (x_i' \cdot v)^2 = \sum_{i=1}^M v^T \cdot x_i'^T \cdot x_i' \cdot v = v^T \cdot (\sum_{i=1}^M x_i'^T \cdot x_i) \cdot v.$$
Well well, suddenly the covariance matrix popped out. Let's denote it simply by $X$. It means we are now looking for a unit vector $v$ that maximizes $v^T \cdot X \cdot v$, for some semi-positive definite matrix $X$.
Now, let's take the eigenvectors and eigenvalues of matrix $X$, and denote them by $e_1, e_2, \dots , e_n$ and $\lambda_1 , \dots, \lambda_n$ respectively, such that $\lambda_1 \geq \lambda_2 , \geq \lambda_3 \dots $. If the values $\lambda$ do not duplicate, eigenvectors form an orthonormal basis. If they do, we choose the eigenvectors in a way that they form an orthonormal basis.
Now let's calculate $v^T \cdot X \cdot v$ for an eigenvector $e_i$. We have $$e_i^T \cdot X \cdot e_i = e_i^T \cdot (\lambda_i e_i) = \lambda_i (\|e_i\|_2)^2 = \lambda_i.$$
Pretty good, this gives us $\lambda_1$ for $e_1$. Now let's take an arbitrary vector $v$. Since eigenvectors form an orthonormal basis, we can write $v = \sum_{i=1}^n e_i \langle v, e_i \rangle$, and we have $\sum_{i=1}^n \langle v, e_i \rangle^2 = 1$. Let's denote $\beta_i = \langle v, e_i \rangle$.
Now let's count $v^T \cdot X \cdot v$. We rewrite $v$ as a linear combination of $e_i$, and get: $$(\sum_{i=1}^n \beta_i e_i)^T \cdot X \cdot (\sum_{i=1}^n \beta_i e_i) = (\sum_{i=1}^n \beta_i e_i) \cdot (\sum_{i=1}^n \lambda_i \beta_i e_i) = \sum_{i=1}^n \lambda_i (\beta_i)^2 (\|e_i\|_2)^2.$$
The last equation comes from the fact the eigenvectors where chosen to be pairwise orthogonal, so their dot products are zero. Now, because all eigenvectors are also of unit length, we can write $v^T \cdot X \cdot v = \sum_{i=1}^n \lambda_i \beta_i^2$, where $\beta_i ^2$ are all positive, and sum to $1$.
That means that the variance of the projection is a weighted mean of eigenvalues. Certainly, it is always less then the biggest eigenvalue, which is why it should be our choice of the first PCA vector.
Now suppose we want another vector. We should chose it from the space orthogonal to the already chosen one, that means the subspace $\mathrm{lin}(e_2, e_3, \dots , e_n)$. By analogical inference we arrive at the conclusion, that the best vector to project on is $e_2$. And so on, and so on...
By the way, it should be now clear, why the variance retained can be expressed by $\sum_{i=1}^k \lambda_i / \sum_{i=1}^n \lambda_i$.
We should also justify the greedy choice of vectors. When we want to choose $k$ vectors to project onto, it might not be the best idea to first choose the best vector, then the best from what remains and so on. I'd like to argue that in this case it is justified and makes no difference. Lets denote the $k$ vector we wish to project onto by $v_1, \dots , v_k$. Also, let's assume the vectors are pairwise orthogonal. As we already know, the total variance of the projections on those vectors can be expressed by $$\sum_{j=1}^k \sum_{i=1}^n \lambda_i \beta_{ij}^2 = \sum_{i=1}^n \lambda_i \gamma_i$$ where $\gamma_i = \sum_{j=1}^k \beta_{ij}^2.$
Now, let's write $e_i$ in some orthonormal basis that includes $v_1, \dots , v_k$. Let's denote the rest of the basis as $u_1, \dots, u_{n-k}$. We can see that $e_i = \sum_{j=1}^k \beta_{ij} v_j + \sum_{j=1}^{n-k} \theta_j \langle e_i, u_j \rangle$.
Because $\|e_i\|_2 = 1$, we have $\sum_{j=1}^k \beta_{ij}^2 + \sum_{j=1}^{n-k} \theta_j^2 = 1$, and hence $\gamma_i \leq 1$ for all $i$.
Now we have a similar case to one vector only, we now know that the total variance of projections is $\sum_{i=1}^n \lambda_i \gamma_i$ with $\gamma_i \leq 1$ and $\sum_{i=1}^n \gamma_i = k$. This is yet another weighted mean, and is certainly no more than $\sum_{i=1}^k \lambda_i$ which corresponds to projecting on $k$ eigenvectors corresponding to biggest eigenvalues. | Making sense of principal component analysis, eigenvectors & eigenvalues | I can give you my own explanation/proof of the PCA, which I think is really simple and elegant, and doesn't require anything except basic knowledge of linear algebra. It came out pretty lengthy, becau | Making sense of principal component analysis, eigenvectors & eigenvalues
I can give you my own explanation/proof of the PCA, which I think is really simple and elegant, and doesn't require anything except basic knowledge of linear algebra. It came out pretty lengthy, because I wanted to write in simple accessible language.
Suppose we have some $M$ samples of data from an $n$-dimensional space. Now we want to project this data on a few lines in the $n$-dimensional space, in a way that retains as much variance as possible (that means, the variance of the projected data should be as big compared to the variance of original data as possible).
Now, let's observe that if we translate (move) all the points by some vector $\beta$, the variance will remain the same, since moving all points by $\beta$ will move their arithmetic mean by $\beta$ as well, and variance is linearly proportional to $\sum_{i=1}^M \|x_i - \mu\|^2$. Hence we translate all the points by $-\mu$, so that their arithmetic mean becomes $0$, for computational comfort. Let's denote the translated points as $x_i' = x_i - \mu$. Let's also observe, that the variance can be now expressed simply as $\sum_{i=1}^M \|x_i'\|^2$.
Now the choice of the line. We can describe any line as set of points that satisfy the equation $x = \alpha v + w$, for some vectors $v,w$. Note that if we move the line by some vector $\gamma$ orthogonal to $v$, then all the projections on the line will also be moved by $\gamma$, hence the mean of the projections will be moved by $\gamma$, hence the variance of the projections will remain unchanged. That means we can move the line parallel to itself, and not change the variance of projections on this line. Again for convenience purposes let's limit ourselves to only the lines passing through the zero point (this means lines described by $x = \alpha v$).
Alright, now suppose we have a vector $v$ that describes the direction of a line that is a possible candidate for the line we search for. We need to calculate variance of the projections on the line $\alpha v$. What we will need are projection points and their mean. From linear algebra we know that in this simple case the projection of $x_i'$ on $\alpha v$ is $\langle x_i, v\rangle/\|v\|_2$. Let's from now on limit ourselves to only unit vectors $v$. That means we can write the length of projection of point $x_i'$ on $v$ simply as $\langle x_i', v\rangle$.
In some of the previous answers someone said that PCA minimizes the sum of squares of distances from the chosen line. We can now see it's true, because sum of squares of projections plus sum of squares of distances from the chosen line is equal to the sum of squares of distances from point $0$. By maximizing the sum of squares of projections, we minimize the sum of squares of distances and vice versa, but this was just a thoughtful digression, back to the proof now.
As for the mean of the projections, let's observe that $v$ is part of some orthogonal basis of our space, and that if we project our data points on every vector of that basis, their sum will cancel out (it's like that because projecting on the vectors from the basis is like writing the data points in the new orthogonal basis). So the sum of all the projections on the vector $v$ (let's call the sum $S_v$) and the sum of projections on other vectors from the basis (let's call it $S_o$) is 0, because it's the mean of the data points. But $S_v$ is orthogonal to $S_o$! That means $S_o = S_v = 0$.
So the mean of our projections is $0$. Well, that's convenient, because that means the variance is just the sum of squares of lengths of projections, or in symbols $$\sum_{i=1}^M (x_i' \cdot v)^2 = \sum_{i=1}^M v^T \cdot x_i'^T \cdot x_i' \cdot v = v^T \cdot (\sum_{i=1}^M x_i'^T \cdot x_i) \cdot v.$$
Well well, suddenly the covariance matrix popped out. Let's denote it simply by $X$. It means we are now looking for a unit vector $v$ that maximizes $v^T \cdot X \cdot v$, for some semi-positive definite matrix $X$.
Now, let's take the eigenvectors and eigenvalues of matrix $X$, and denote them by $e_1, e_2, \dots , e_n$ and $\lambda_1 , \dots, \lambda_n$ respectively, such that $\lambda_1 \geq \lambda_2 , \geq \lambda_3 \dots $. If the values $\lambda$ do not duplicate, eigenvectors form an orthonormal basis. If they do, we choose the eigenvectors in a way that they form an orthonormal basis.
Now let's calculate $v^T \cdot X \cdot v$ for an eigenvector $e_i$. We have $$e_i^T \cdot X \cdot e_i = e_i^T \cdot (\lambda_i e_i) = \lambda_i (\|e_i\|_2)^2 = \lambda_i.$$
Pretty good, this gives us $\lambda_1$ for $e_1$. Now let's take an arbitrary vector $v$. Since eigenvectors form an orthonormal basis, we can write $v = \sum_{i=1}^n e_i \langle v, e_i \rangle$, and we have $\sum_{i=1}^n \langle v, e_i \rangle^2 = 1$. Let's denote $\beta_i = \langle v, e_i \rangle$.
Now let's count $v^T \cdot X \cdot v$. We rewrite $v$ as a linear combination of $e_i$, and get: $$(\sum_{i=1}^n \beta_i e_i)^T \cdot X \cdot (\sum_{i=1}^n \beta_i e_i) = (\sum_{i=1}^n \beta_i e_i) \cdot (\sum_{i=1}^n \lambda_i \beta_i e_i) = \sum_{i=1}^n \lambda_i (\beta_i)^2 (\|e_i\|_2)^2.$$
The last equation comes from the fact the eigenvectors where chosen to be pairwise orthogonal, so their dot products are zero. Now, because all eigenvectors are also of unit length, we can write $v^T \cdot X \cdot v = \sum_{i=1}^n \lambda_i \beta_i^2$, where $\beta_i ^2$ are all positive, and sum to $1$.
That means that the variance of the projection is a weighted mean of eigenvalues. Certainly, it is always less then the biggest eigenvalue, which is why it should be our choice of the first PCA vector.
Now suppose we want another vector. We should chose it from the space orthogonal to the already chosen one, that means the subspace $\mathrm{lin}(e_2, e_3, \dots , e_n)$. By analogical inference we arrive at the conclusion, that the best vector to project on is $e_2$. And so on, and so on...
By the way, it should be now clear, why the variance retained can be expressed by $\sum_{i=1}^k \lambda_i / \sum_{i=1}^n \lambda_i$.
We should also justify the greedy choice of vectors. When we want to choose $k$ vectors to project onto, it might not be the best idea to first choose the best vector, then the best from what remains and so on. I'd like to argue that in this case it is justified and makes no difference. Lets denote the $k$ vector we wish to project onto by $v_1, \dots , v_k$. Also, let's assume the vectors are pairwise orthogonal. As we already know, the total variance of the projections on those vectors can be expressed by $$\sum_{j=1}^k \sum_{i=1}^n \lambda_i \beta_{ij}^2 = \sum_{i=1}^n \lambda_i \gamma_i$$ where $\gamma_i = \sum_{j=1}^k \beta_{ij}^2.$
Now, let's write $e_i$ in some orthonormal basis that includes $v_1, \dots , v_k$. Let's denote the rest of the basis as $u_1, \dots, u_{n-k}$. We can see that $e_i = \sum_{j=1}^k \beta_{ij} v_j + \sum_{j=1}^{n-k} \theta_j \langle e_i, u_j \rangle$.
Because $\|e_i\|_2 = 1$, we have $\sum_{j=1}^k \beta_{ij}^2 + \sum_{j=1}^{n-k} \theta_j^2 = 1$, and hence $\gamma_i \leq 1$ for all $i$.
Now we have a similar case to one vector only, we now know that the total variance of projections is $\sum_{i=1}^n \lambda_i \gamma_i$ with $\gamma_i \leq 1$ and $\sum_{i=1}^n \gamma_i = k$. This is yet another weighted mean, and is certainly no more than $\sum_{i=1}^k \lambda_i$ which corresponds to projecting on $k$ eigenvectors corresponding to biggest eigenvalues. | Making sense of principal component analysis, eigenvectors & eigenvalues
I can give you my own explanation/proof of the PCA, which I think is really simple and elegant, and doesn't require anything except basic knowledge of linear algebra. It came out pretty lengthy, becau |
7 | Making sense of principal component analysis, eigenvectors & eigenvalues | Alright, I'll give this a try. A few months back I dug through a good amount of literature to find an intuitive explanation I could explain to a non-statistician. I found the derivations that use Lagrange multipliers the most intuitive.
Let's say we have high dimension data - say 30 measurements made on an insect. The bugs have different genotypes and slightly different physical features in some of these dimensions, but with such high dimension data it's hard to tell which insects belong to which group.
PCA is a technique to reduce dimension by:
Taking linear combinations of the original variables.
Each linear combination explains the most variance in the data it can.
Each linear combination is uncorrelated with the others
Or, in mathematical terms:
For $Y_j = a_j' x$ (linear combination for jth component)
For $k > j$, $V(Y_k) < V(Y_j)$ (first components explain more variation)
$a_k' a_j = 0$ (orthogonality)
Finding linear combinations that satisfy these constraints leads us to eigenvalues. Why?
I recommend checking out the book An Introduction to Multivariate Data Analysis for the full derivation (p. 50), but the basic idea is successive optimizations problems (maximizing variance) constrained such that a'a = 1 for coefficients a (to prevent the case when variance could be infinite) and constrained to make sure the coefficients are orthogonal.
This leads to optimization with Lagrange multipliers, which in turn reveals why eigenvalues are used. I am too lazy to type it out (sorry!) but, this PDF goes through the proof pretty well from this point.
I would never try to explain this to my grandmother, but if I had to talk generally about dimension reduction techniques, I'd point to this trivial projection example (not PCA). Suppose you have a Calder mobile that is very complex. Some points in 3-d space close to each other, others aren't. If we hung this mobile from the ceiling and shined light on it from one angle, we get a projection onto a lower dimension plane (a 2-d wall). Now, if this mobile is mainly wide in one direction, but skinny in the other direction, we can rotate it to get projections that differ in usefulness. Intuitively, a skinny shape in one dimension projected on a wall is less useful - all the shadows overlap and don't give us much information. However, if we rotate it so the light shines on the wide side, we get a better picture of the reduced dimension data - points are more spread out. This is often what we want. I think my grandmother could understand that :-) | Making sense of principal component analysis, eigenvectors & eigenvalues | Alright, I'll give this a try. A few months back I dug through a good amount of literature to find an intuitive explanation I could explain to a non-statistician. I found the derivations that use Lagr | Making sense of principal component analysis, eigenvectors & eigenvalues
Alright, I'll give this a try. A few months back I dug through a good amount of literature to find an intuitive explanation I could explain to a non-statistician. I found the derivations that use Lagrange multipliers the most intuitive.
Let's say we have high dimension data - say 30 measurements made on an insect. The bugs have different genotypes and slightly different physical features in some of these dimensions, but with such high dimension data it's hard to tell which insects belong to which group.
PCA is a technique to reduce dimension by:
Taking linear combinations of the original variables.
Each linear combination explains the most variance in the data it can.
Each linear combination is uncorrelated with the others
Or, in mathematical terms:
For $Y_j = a_j' x$ (linear combination for jth component)
For $k > j$, $V(Y_k) < V(Y_j)$ (first components explain more variation)
$a_k' a_j = 0$ (orthogonality)
Finding linear combinations that satisfy these constraints leads us to eigenvalues. Why?
I recommend checking out the book An Introduction to Multivariate Data Analysis for the full derivation (p. 50), but the basic idea is successive optimizations problems (maximizing variance) constrained such that a'a = 1 for coefficients a (to prevent the case when variance could be infinite) and constrained to make sure the coefficients are orthogonal.
This leads to optimization with Lagrange multipliers, which in turn reveals why eigenvalues are used. I am too lazy to type it out (sorry!) but, this PDF goes through the proof pretty well from this point.
I would never try to explain this to my grandmother, but if I had to talk generally about dimension reduction techniques, I'd point to this trivial projection example (not PCA). Suppose you have a Calder mobile that is very complex. Some points in 3-d space close to each other, others aren't. If we hung this mobile from the ceiling and shined light on it from one angle, we get a projection onto a lower dimension plane (a 2-d wall). Now, if this mobile is mainly wide in one direction, but skinny in the other direction, we can rotate it to get projections that differ in usefulness. Intuitively, a skinny shape in one dimension projected on a wall is less useful - all the shadows overlap and don't give us much information. However, if we rotate it so the light shines on the wide side, we get a better picture of the reduced dimension data - points are more spread out. This is often what we want. I think my grandmother could understand that :-) | Making sense of principal component analysis, eigenvectors & eigenvalues
Alright, I'll give this a try. A few months back I dug through a good amount of literature to find an intuitive explanation I could explain to a non-statistician. I found the derivations that use Lagr |
8 | Making sense of principal component analysis, eigenvectors & eigenvalues | Trying to be non-technical... Imagine you have a multivariate data, a multidimensional cloud of points. When you compute covariance matrix of those you actually (a) center the cloud, i.e. put the origin as the multidimensional mean, the coordinate system axes now cross in the centre of the cloud, (b) encrypt the information about the shape of the cloud and how it is oriented in the space by means of variance-covariance entries. So, most of the important info about the shape of the data as a whole is stored in the covariance matrix.
Then you do eigen-decomposition of that martrix and obtain the list of eigenvalues and the corresponding number of eigenvectors. Now, the 1st principal component is the new, latent variable which can be displayed as the axis going through the origin and oriented along the direction of the maximal variance (thickness) of the cloud. The variance along this axis, i.e. the variance of the coordinates of all points on it, is the first eigenvalue, and the orientation of the axis in space referenced to the original axes (the variables) is defined by the 1st eigenvector: its entries are the cosines between it and those original axes. The aforementioned coordinates of data points on the 1st component are the 1st principal component values, or component scores; they are computed as the product of (centered) data matrix and the eigenvector.
"After" the 1st pr. component got measured it is, to say, "removed" from the cloud with all the variance it accounted for, and the dimensionality of the cloud drops by one. Next, everything is repeated with the second eigenvalue and the second eigenvector - the 2nd pr. component is being recorded, and then "removed". Etc.
So, once again: eigenvectors are direction cosines for principal components, while eigenvalues are the magnitude (the variance) in the principal components. Sum of all eigenvalues is equal to the sum of variances which are on the diagonal of the variance-covariance matrix. If you transfer the "magnitudinal" information stored in eigenvalues over to eigenvectors to add it to the "orientational" information stored therein you get what is called principal component loadings; these loadings - because they carry both types of information - are the covariances between the original variables and the principal components.
Later P.S. I want especially to stress twice here the terminologic difference between eigenvectors and loadings. Many people and some packages (including some of R) flippantly use the two terms interchangeably. It is a bad practice because the objects and their meanings are different. Eigenvectors are the direction cosines, the angle of the orthogonal "rotation" which PCA amounts to. Loadings are eigenvectors inoculated with the information about the variability or magnitude of the rotated data. The loadings are the association coefficients between the components and the variables and they are directly comparable with the association coefficients computed between the variables - covariances, correlations or other scalar products, on which you base your PCA. Both eigenvectors and loadings are similar in respect that they serve regressional coefficients in predicting the variables by the components (not vice versa!$^1$). Eigenvectors are the coefficients to predict variables by raw component scores. Loadings are the coefficients to predict variables by scaled (normalized) component scores (no wonder: loadings have precipitated information on the variability, consequently, components used must be deprived of it). One more reason not to mix eigenvectors and loadings is that some other dimensionality reduction techiques besides PCA - such as some forms of Factor analysis - compute loadings directly, bypassing eigenvectors. Eigenvectors are the product of eigen-decomposition or singular-value decomposition; some forms of factor analysis do not use these decompositions and arrive at loadings other way around. Finally, it is loadings, not eigenvectors, by which you interpret the components or factors (if you need to interpret them). Loading is about a contribution of component into a variable: in PCA (or factor analysis) component/factor loads itself onto variable, not vice versa. In a comprehensive PCA results one should report both eigenvectors and loadings, as shown e.g. here or here.
See also about loadings vs eigenvectors.
$^1$ Since eigenvector matrix in PCA is orthonormal and its inverse is its transpose, we may say that those same eigenvectors are also the coefficients to back predict the components by the variables. It is not so for loadings, though. | Making sense of principal component analysis, eigenvectors & eigenvalues | Trying to be non-technical... Imagine you have a multivariate data, a multidimensional cloud of points. When you compute covariance matrix of those you actually (a) center the cloud, i.e. put the orig | Making sense of principal component analysis, eigenvectors & eigenvalues
Trying to be non-technical... Imagine you have a multivariate data, a multidimensional cloud of points. When you compute covariance matrix of those you actually (a) center the cloud, i.e. put the origin as the multidimensional mean, the coordinate system axes now cross in the centre of the cloud, (b) encrypt the information about the shape of the cloud and how it is oriented in the space by means of variance-covariance entries. So, most of the important info about the shape of the data as a whole is stored in the covariance matrix.
Then you do eigen-decomposition of that martrix and obtain the list of eigenvalues and the corresponding number of eigenvectors. Now, the 1st principal component is the new, latent variable which can be displayed as the axis going through the origin and oriented along the direction of the maximal variance (thickness) of the cloud. The variance along this axis, i.e. the variance of the coordinates of all points on it, is the first eigenvalue, and the orientation of the axis in space referenced to the original axes (the variables) is defined by the 1st eigenvector: its entries are the cosines between it and those original axes. The aforementioned coordinates of data points on the 1st component are the 1st principal component values, or component scores; they are computed as the product of (centered) data matrix and the eigenvector.
"After" the 1st pr. component got measured it is, to say, "removed" from the cloud with all the variance it accounted for, and the dimensionality of the cloud drops by one. Next, everything is repeated with the second eigenvalue and the second eigenvector - the 2nd pr. component is being recorded, and then "removed". Etc.
So, once again: eigenvectors are direction cosines for principal components, while eigenvalues are the magnitude (the variance) in the principal components. Sum of all eigenvalues is equal to the sum of variances which are on the diagonal of the variance-covariance matrix. If you transfer the "magnitudinal" information stored in eigenvalues over to eigenvectors to add it to the "orientational" information stored therein you get what is called principal component loadings; these loadings - because they carry both types of information - are the covariances between the original variables and the principal components.
Later P.S. I want especially to stress twice here the terminologic difference between eigenvectors and loadings. Many people and some packages (including some of R) flippantly use the two terms interchangeably. It is a bad practice because the objects and their meanings are different. Eigenvectors are the direction cosines, the angle of the orthogonal "rotation" which PCA amounts to. Loadings are eigenvectors inoculated with the information about the variability or magnitude of the rotated data. The loadings are the association coefficients between the components and the variables and they are directly comparable with the association coefficients computed between the variables - covariances, correlations or other scalar products, on which you base your PCA. Both eigenvectors and loadings are similar in respect that they serve regressional coefficients in predicting the variables by the components (not vice versa!$^1$). Eigenvectors are the coefficients to predict variables by raw component scores. Loadings are the coefficients to predict variables by scaled (normalized) component scores (no wonder: loadings have precipitated information on the variability, consequently, components used must be deprived of it). One more reason not to mix eigenvectors and loadings is that some other dimensionality reduction techiques besides PCA - such as some forms of Factor analysis - compute loadings directly, bypassing eigenvectors. Eigenvectors are the product of eigen-decomposition or singular-value decomposition; some forms of factor analysis do not use these decompositions and arrive at loadings other way around. Finally, it is loadings, not eigenvectors, by which you interpret the components or factors (if you need to interpret them). Loading is about a contribution of component into a variable: in PCA (or factor analysis) component/factor loads itself onto variable, not vice versa. In a comprehensive PCA results one should report both eigenvectors and loadings, as shown e.g. here or here.
See also about loadings vs eigenvectors.
$^1$ Since eigenvector matrix in PCA is orthonormal and its inverse is its transpose, we may say that those same eigenvectors are also the coefficients to back predict the components by the variables. It is not so for loadings, though. | Making sense of principal component analysis, eigenvectors & eigenvalues
Trying to be non-technical... Imagine you have a multivariate data, a multidimensional cloud of points. When you compute covariance matrix of those you actually (a) center the cloud, i.e. put the orig |
9 | Making sense of principal component analysis, eigenvectors & eigenvalues | It's easiest to do the maths in 2-D.
Every matrix corresponds to a linear transformation. Linear transformations can be visualised by taking a memorable figure on the plane and seeing how that figure is distorted by the linear transform:
(pic: Flanigan & Kazdan)
Eigenvectors are the stay-the-same vectors. They point in the same direction after the transform as they used to. (blue stayed the same, so that direction is an eigenvector of $\tt{shear}$.)
Eigenvalues are how much the stay-the-same vectors grow or shrink. (blue stayed the same size so the eigenvalue would be $\times 1$.)
PCA rotates your axes to "line up" better with your data.
(source: weigend.com) PCA uses the eigenvectors of the covariance matrix to figure out how you should rotate the data. Because rotation is a kind of linear transformation, your new dimensions will be sums of the old ones, like $\langle 1 \rangle = 23\% \cdot [1] + 46\% \cdot [2] + 39\% \cdot [3]$.
The reason people who work with real data are interested in eigenvectors and linear transformations is that in different contexts, "linear" ($f(a\cdot x+b\cdot y)=a\cdot f(x)+b \cdot f(y)$) can cover really interesting stuff. For example think what that property means if $+$ and $\cdot$ are given new meanings, or if $a$ and $b$ come from some interesting field, or $x$ and $y$ from some interesting space. For example:
PCA itself is another example, the one most familiar to statisticians. Some of the other answers like Freya's give real-world applications of PCA.
$${}$$
$\dagger$ I find it totally surprising that something as simple as "rotation" could do so many things in different areas, like lining up products for a recommender system $\overset{\text{similar how?}}{\longleftarrow\!\!\!-\!\!-\!\!-\!\!-\!\!-\!\!\!\longrightarrow}$ explaining geopolitical conflict. But maybe it's not so surprising if you think about physics, where choosing a better basis (e.g. making the $\mathrm{x}$ axis the direction of motion rather than $42.8\% [\mathrm{x}] \oplus 57.2\% [\mathrm{y}]$ will change inscrutable equations into simple ones). | Making sense of principal component analysis, eigenvectors & eigenvalues | It's easiest to do the maths in 2-D.
Every matrix corresponds to a linear transformation. Linear transformations can be visualised by taking a memorable figure on the plane and seeing how that figure | Making sense of principal component analysis, eigenvectors & eigenvalues
It's easiest to do the maths in 2-D.
Every matrix corresponds to a linear transformation. Linear transformations can be visualised by taking a memorable figure on the plane and seeing how that figure is distorted by the linear transform:
(pic: Flanigan & Kazdan)
Eigenvectors are the stay-the-same vectors. They point in the same direction after the transform as they used to. (blue stayed the same, so that direction is an eigenvector of $\tt{shear}$.)
Eigenvalues are how much the stay-the-same vectors grow or shrink. (blue stayed the same size so the eigenvalue would be $\times 1$.)
PCA rotates your axes to "line up" better with your data.
(source: weigend.com) PCA uses the eigenvectors of the covariance matrix to figure out how you should rotate the data. Because rotation is a kind of linear transformation, your new dimensions will be sums of the old ones, like $\langle 1 \rangle = 23\% \cdot [1] + 46\% \cdot [2] + 39\% \cdot [3]$.
The reason people who work with real data are interested in eigenvectors and linear transformations is that in different contexts, "linear" ($f(a\cdot x+b\cdot y)=a\cdot f(x)+b \cdot f(y)$) can cover really interesting stuff. For example think what that property means if $+$ and $\cdot$ are given new meanings, or if $a$ and $b$ come from some interesting field, or $x$ and $y$ from some interesting space. For example:
PCA itself is another example, the one most familiar to statisticians. Some of the other answers like Freya's give real-world applications of PCA.
$${}$$
$\dagger$ I find it totally surprising that something as simple as "rotation" could do so many things in different areas, like lining up products for a recommender system $\overset{\text{similar how?}}{\longleftarrow\!\!\!-\!\!-\!\!-\!\!-\!\!-\!\!\!\longrightarrow}$ explaining geopolitical conflict. But maybe it's not so surprising if you think about physics, where choosing a better basis (e.g. making the $\mathrm{x}$ axis the direction of motion rather than $42.8\% [\mathrm{x}] \oplus 57.2\% [\mathrm{y}]$ will change inscrutable equations into simple ones). | Making sense of principal component analysis, eigenvectors & eigenvalues
It's easiest to do the maths in 2-D.
Every matrix corresponds to a linear transformation. Linear transformations can be visualised by taking a memorable figure on the plane and seeing how that figure |
10 | Making sense of principal component analysis, eigenvectors & eigenvalues | After the excellent post by JD Long in this thread, I looked for a simple example, and the R code necessary to produce the PCA and then go back to the original data. It gave me some first-hand geometric intuition, and I want to share what I got. The dataset and code can be directly copied and pasted into R form Github.
I used a data set that I found online on semiconductors here, and I trimmed it to just two dimensions - "atomic number" and "melting point" - to facilitate plotting.
As a caveat the idea is purely illustrative of the computational process: PCA is used to reduce more than two variables to a few derived principal components, or to identify collinearity also in the case of multiple features. So it wouldn't find much application in the case of two variables, nor would there be a need to calculate eigenvectors of correlation matrices as pointed out by @amoeba.
Further, I truncated the observations from 44 to 15 to ease the task of tracking individual points. The ultimate result was a skeleton data frame (dat1):
compounds atomic.no melting.point
AIN 10 498.0
AIP 14 625.0
AIAs 23 1011.5
... ... ...
The "compounds" column indicate the chemical constitution of the semiconductor, and plays the role of row name.
This can be reproduced as follows (ready to copy and paste on R console):
# install.packages('gsheet')
library(gsheet)
dat <- read.csv(url("https://raw.githubusercontent.com/RInterested/DATASETS/gh-pages/semiconductors.csv"))
colnames(dat)[2] <- "atomic.no"
dat1 <- subset(dat[1:15,1:3])
row.names(dat1) <- dat1$compounds
dat1 <- dat1[,-1]
The data were then scaled:
X <- apply(dat1, 2, function(x) (x - mean(x)) / sd(x))
# This centers data points around the mean and standardizes by dividing by SD.
# It is the equivalent to `X <- scale(dat1, center = T, scale = T)`
The linear algebra steps followed:
C <- cov(X) # Covariance matrix (centered data)
$\begin{bmatrix}
&\text{at_no}&\text{melt_p}\\
\text{at_no}&1&0.296\\
\text{melt_p}&0.296&1
\end{bmatrix}$
The correlation function cor(dat1) gives the same output on the non-scaled data as the function cov(X) on the scaled data.
lambda <- eigen(C)$values # Eigenvalues
lambda_matrix <- diag(2)*eigen(C)$values # Eigenvalues matrix
$\begin{bmatrix}
&\color{purple}{\lambda_{\text{PC1}}}&\color{orange}{\lambda_{\text{PC2}}}\\
&1.296422& 0\\
&0&0.7035783
\end{bmatrix}$
e_vectors <- eigen(C)$vectors # Eigenvectors
$\frac{1}{\sqrt{2}}\begin{bmatrix}
&\color{purple}{\text{PC1}}&\color{orange}{\text{PC2}}\\
&1&\,\,\,\,\,1\\
&1&-1
\end{bmatrix}$
Since the first eigenvector initially returns as $\sim \small [-0.7,-0.7]$ we choose to change it to $\small [0.7, 0.7]$ to make it consistent with built-in formulas through:
e_vectors[,1] = - e_vectors[,1]; colnames(e_vectors) <- c("PC1","PC2")
The resultant eigenvalues were $\small 1.2964217$ and $\small 0.7035783$. Under less minimalistic conditions, this result would have helped decide which eigenvectors to include (largest eigenvalues). For instance, the relative contribution of the first eigenvalue is $\small 64.8\%$: eigen(C)$values[1]/sum(eigen(C)$values) * 100, meaning that it accounts for $\sim\small 65\%$ of the variability in the data. The variability in the direction of the second eigenvector is $35.2\%$. This is typically shown on a scree plot depicting the value of the eigenvalues:
We'll include both eigenvectors given the small size of this toy data set example, understanding that excluding one of the eigenvectors would result in dimensionality reduction - the idea behind PCA.
The score matrix was determined as the matrix multiplication of the scaled data (X) by the matrix of eigenvectors (or "rotations"):
score_matrix <- X %*% e_vectors
# Identical to the often found operation: t(t(e_vectors) %*% t(X))
The concept entails a linear combination of each entry (row / subject / observation / superconductor in this case) of the centered (and in this case scaled) data weighted by the rows of each eigenvector, so that in each of the final columns of the score matrix, we'll find a contribution from each variable (column) of the data (the entire X), BUT only the corresponding eigenvector will have taken part in the computation (i.e. the first eigenvector $[0.7, 0.7]^{T}$ will contribute to $\text{PC}\,1$ (Principal Component 1) and $[0.7, -0.7]^{T}$ to $\text{PC}\,2$, as in:
Therefore each eigenvector will influence each variable differently, and this will be reflected in the "loadings" of the PCA. In our case, the negative sign in the second component of the second eigenvector $[0.7, - 0.7]$ will change the sign of the melting point values in the linear combinations that produce PC2, whereas the effect of the first eigenvector will be consistently positive:
The eigenvectors are scaled to $1$:
> apply(e_vectors, 2, function(x) sum(x^2))
PC1 PC2
1 1
whereas the (loadings) are the eigenvectors scaled by the eigenvalues (despite the confusing terminology in the in-built R functions displayed below). Consequently, the loadings can be calculated as:
> e_vectors %*% lambda_matrix
[,1] [,2]
[1,] 0.9167086 0.497505
[2,] 0.9167086 -0.497505
> prcomp(X)$rotation %*% diag(princomp(covmat = C)$sd^2)
[,1] [,2]
atomic.no 0.9167086 0.497505
melting.point 0.9167086 -0.497505
It is interesting to note that the rotated data cloud (the score plot) will have variance along each component (PC) equal to the eigenvalues:
> apply(score_matrix, 2, function(x) var(x))
PC1 PC2
1.2964217 0.7035783
> lambda
[1] 1.2964217 0.7035783
Utilizing the built-in functions the results can be replicated:
# For the SCORE MATRIX:
prcomp(X)$x
# or...
princomp(X)$scores # The signs of the PC 1 column will be reversed.
# and for EIGENVECTOR MATRIX:
prcomp(X)$rotation
# or...
princomp(X)$loadings
# and for EIGENVALUES:
prcomp(X)$sdev^2
# or...
princomp(covmat = C)$sd^2
Alternatively, the singular value decomposition ($\text{U}\Sigma \text{V}^\text{T}$) method can be applied to manually calculate PCA; in fact, this is the method used in prcomp(). The steps can be spelled out as:
svd_scaled_dat <-svd(scale(dat1))
eigen_vectors <- svd_scaled_dat$v
eigen_values <- (svd_scaled_dat$d/sqrt(nrow(dat1) - 1))^2
scores<-scale(dat1) %*% eigen_vectors
The result is shown below, with first, the distances from the individual points to the first eigenvector, and on a second plot, the orthogonal distances to the second eigenvector:
If instead we plotted the values of the score matrix (PC1 and PC2) - no longer "melting.point" and "atomic.no", but really a change of basis of the point coordinates with the eigenvectors as basis, these distances would be preserved, but would naturally become perpendicular to the xy axis:
The trick was now to recover the original data. The points had been transformed through a simple matrix multiplication by the eigenvectors. Now the data was rotated back by multiplying by the inverse of the matrix of eigenvectors with a resultant marked change in the location of the data points. For instance, notice the change in pink dot "GaN" in the left upper quadrant (black circle in the left plot, below), returning to its initial position in the left lower quadrant (black circle in the right plot, below).
Now we finally had the original data restored in this "de-rotated" matrix:
Beyond the change of coordinates of rotation of the data in PCA, the results must be interpreted, and this process tends to involve a biplot, on which the data points are plotted with respect to the new eigenvector coordinates, and the original variables are now superimposed as vectors. It is interesting to note the equivalence in the position of the points between the plots in the second row of rotation graphs above ("Scores with xy Axis = Eigenvectors") (to the left in the plots that follow), and the biplot (to the right):
The superimposition of the original variables as red arrows offers a path to the interpretation of PC1 as a vector in the direction (or with a positive correlation) with both atomic no and melting point; and of PC2 as a component along increasing values of atomic no but negatively correlated with melting point, consistent with the values of the eigenvectors:
PCA <- prcomp(dat1, center = T, scale = T)
PCA$rotation
PC1 PC2
atomic.no 0.7071068 0.7071068
melting.point 0.7071068 -0.7071068
As a final point, it is legitimate to wonder if, at the end of the day, we are simply doing ordinary least squares in a different way, using the eigenvectors to define hyperplanes through data clouds, because of the obvious similarities. To begin with the objective in both methods is different: PCA is meant to reduce dimensionality to understand the main drivers in the variability of datasets, whereas OLS is intended to extract the relationship between a "dependent" variable and one or multiple explanatory variables.
In the case of a single explanatory variable as in the toy example in this post, we can also superimpose the OLS regression line on the data cloud to note how OLS reduces the sum of vertical squared distances from the fitted line to the points, as opposed to orthogonal lines to the eigenvector in question:
In OLS the squared residuals are the hypothenuses of the perpendiculars from the points to the OLS line, and hence result in a higher sum of squared residuals (12.77) than the sum of the squared perpendicular segments from the points to the OLS line (11.74). The latter is what PCA is optimized for: (Wikipedia) "PCA quantifies data representation as the aggregate of the L2-norm of the data point projections into the subspace, or equivalently the aggregate Euclidean distance of the original points from their subspace-projected representations." This subspace has the orthogonal eigenvectors of the covariance matrix as a basis. The proof of this statement can be found here together with the pertinent credit to Marc Deisenroth.
Naturally, the fact that the dataset has been scaled and centered at zero, reduces the intercept of the OLS to zero, and the slope to the correlation between the variables, 0.2964.
This interactive tutorial by Victor Powell gives immediate feedback as to the changes in the eigenvectors as the data cloud is modified.
All the code related to this post can be found here. | Making sense of principal component analysis, eigenvectors & eigenvalues | After the excellent post by JD Long in this thread, I looked for a simple example, and the R code necessary to produce the PCA and then go back to the original data. It gave me some first-hand geometr | Making sense of principal component analysis, eigenvectors & eigenvalues
After the excellent post by JD Long in this thread, I looked for a simple example, and the R code necessary to produce the PCA and then go back to the original data. It gave me some first-hand geometric intuition, and I want to share what I got. The dataset and code can be directly copied and pasted into R form Github.
I used a data set that I found online on semiconductors here, and I trimmed it to just two dimensions - "atomic number" and "melting point" - to facilitate plotting.
As a caveat the idea is purely illustrative of the computational process: PCA is used to reduce more than two variables to a few derived principal components, or to identify collinearity also in the case of multiple features. So it wouldn't find much application in the case of two variables, nor would there be a need to calculate eigenvectors of correlation matrices as pointed out by @amoeba.
Further, I truncated the observations from 44 to 15 to ease the task of tracking individual points. The ultimate result was a skeleton data frame (dat1):
compounds atomic.no melting.point
AIN 10 498.0
AIP 14 625.0
AIAs 23 1011.5
... ... ...
The "compounds" column indicate the chemical constitution of the semiconductor, and plays the role of row name.
This can be reproduced as follows (ready to copy and paste on R console):
# install.packages('gsheet')
library(gsheet)
dat <- read.csv(url("https://raw.githubusercontent.com/RInterested/DATASETS/gh-pages/semiconductors.csv"))
colnames(dat)[2] <- "atomic.no"
dat1 <- subset(dat[1:15,1:3])
row.names(dat1) <- dat1$compounds
dat1 <- dat1[,-1]
The data were then scaled:
X <- apply(dat1, 2, function(x) (x - mean(x)) / sd(x))
# This centers data points around the mean and standardizes by dividing by SD.
# It is the equivalent to `X <- scale(dat1, center = T, scale = T)`
The linear algebra steps followed:
C <- cov(X) # Covariance matrix (centered data)
$\begin{bmatrix}
&\text{at_no}&\text{melt_p}\\
\text{at_no}&1&0.296\\
\text{melt_p}&0.296&1
\end{bmatrix}$
The correlation function cor(dat1) gives the same output on the non-scaled data as the function cov(X) on the scaled data.
lambda <- eigen(C)$values # Eigenvalues
lambda_matrix <- diag(2)*eigen(C)$values # Eigenvalues matrix
$\begin{bmatrix}
&\color{purple}{\lambda_{\text{PC1}}}&\color{orange}{\lambda_{\text{PC2}}}\\
&1.296422& 0\\
&0&0.7035783
\end{bmatrix}$
e_vectors <- eigen(C)$vectors # Eigenvectors
$\frac{1}{\sqrt{2}}\begin{bmatrix}
&\color{purple}{\text{PC1}}&\color{orange}{\text{PC2}}\\
&1&\,\,\,\,\,1\\
&1&-1
\end{bmatrix}$
Since the first eigenvector initially returns as $\sim \small [-0.7,-0.7]$ we choose to change it to $\small [0.7, 0.7]$ to make it consistent with built-in formulas through:
e_vectors[,1] = - e_vectors[,1]; colnames(e_vectors) <- c("PC1","PC2")
The resultant eigenvalues were $\small 1.2964217$ and $\small 0.7035783$. Under less minimalistic conditions, this result would have helped decide which eigenvectors to include (largest eigenvalues). For instance, the relative contribution of the first eigenvalue is $\small 64.8\%$: eigen(C)$values[1]/sum(eigen(C)$values) * 100, meaning that it accounts for $\sim\small 65\%$ of the variability in the data. The variability in the direction of the second eigenvector is $35.2\%$. This is typically shown on a scree plot depicting the value of the eigenvalues:
We'll include both eigenvectors given the small size of this toy data set example, understanding that excluding one of the eigenvectors would result in dimensionality reduction - the idea behind PCA.
The score matrix was determined as the matrix multiplication of the scaled data (X) by the matrix of eigenvectors (or "rotations"):
score_matrix <- X %*% e_vectors
# Identical to the often found operation: t(t(e_vectors) %*% t(X))
The concept entails a linear combination of each entry (row / subject / observation / superconductor in this case) of the centered (and in this case scaled) data weighted by the rows of each eigenvector, so that in each of the final columns of the score matrix, we'll find a contribution from each variable (column) of the data (the entire X), BUT only the corresponding eigenvector will have taken part in the computation (i.e. the first eigenvector $[0.7, 0.7]^{T}$ will contribute to $\text{PC}\,1$ (Principal Component 1) and $[0.7, -0.7]^{T}$ to $\text{PC}\,2$, as in:
Therefore each eigenvector will influence each variable differently, and this will be reflected in the "loadings" of the PCA. In our case, the negative sign in the second component of the second eigenvector $[0.7, - 0.7]$ will change the sign of the melting point values in the linear combinations that produce PC2, whereas the effect of the first eigenvector will be consistently positive:
The eigenvectors are scaled to $1$:
> apply(e_vectors, 2, function(x) sum(x^2))
PC1 PC2
1 1
whereas the (loadings) are the eigenvectors scaled by the eigenvalues (despite the confusing terminology in the in-built R functions displayed below). Consequently, the loadings can be calculated as:
> e_vectors %*% lambda_matrix
[,1] [,2]
[1,] 0.9167086 0.497505
[2,] 0.9167086 -0.497505
> prcomp(X)$rotation %*% diag(princomp(covmat = C)$sd^2)
[,1] [,2]
atomic.no 0.9167086 0.497505
melting.point 0.9167086 -0.497505
It is interesting to note that the rotated data cloud (the score plot) will have variance along each component (PC) equal to the eigenvalues:
> apply(score_matrix, 2, function(x) var(x))
PC1 PC2
1.2964217 0.7035783
> lambda
[1] 1.2964217 0.7035783
Utilizing the built-in functions the results can be replicated:
# For the SCORE MATRIX:
prcomp(X)$x
# or...
princomp(X)$scores # The signs of the PC 1 column will be reversed.
# and for EIGENVECTOR MATRIX:
prcomp(X)$rotation
# or...
princomp(X)$loadings
# and for EIGENVALUES:
prcomp(X)$sdev^2
# or...
princomp(covmat = C)$sd^2
Alternatively, the singular value decomposition ($\text{U}\Sigma \text{V}^\text{T}$) method can be applied to manually calculate PCA; in fact, this is the method used in prcomp(). The steps can be spelled out as:
svd_scaled_dat <-svd(scale(dat1))
eigen_vectors <- svd_scaled_dat$v
eigen_values <- (svd_scaled_dat$d/sqrt(nrow(dat1) - 1))^2
scores<-scale(dat1) %*% eigen_vectors
The result is shown below, with first, the distances from the individual points to the first eigenvector, and on a second plot, the orthogonal distances to the second eigenvector:
If instead we plotted the values of the score matrix (PC1 and PC2) - no longer "melting.point" and "atomic.no", but really a change of basis of the point coordinates with the eigenvectors as basis, these distances would be preserved, but would naturally become perpendicular to the xy axis:
The trick was now to recover the original data. The points had been transformed through a simple matrix multiplication by the eigenvectors. Now the data was rotated back by multiplying by the inverse of the matrix of eigenvectors with a resultant marked change in the location of the data points. For instance, notice the change in pink dot "GaN" in the left upper quadrant (black circle in the left plot, below), returning to its initial position in the left lower quadrant (black circle in the right plot, below).
Now we finally had the original data restored in this "de-rotated" matrix:
Beyond the change of coordinates of rotation of the data in PCA, the results must be interpreted, and this process tends to involve a biplot, on which the data points are plotted with respect to the new eigenvector coordinates, and the original variables are now superimposed as vectors. It is interesting to note the equivalence in the position of the points between the plots in the second row of rotation graphs above ("Scores with xy Axis = Eigenvectors") (to the left in the plots that follow), and the biplot (to the right):
The superimposition of the original variables as red arrows offers a path to the interpretation of PC1 as a vector in the direction (or with a positive correlation) with both atomic no and melting point; and of PC2 as a component along increasing values of atomic no but negatively correlated with melting point, consistent with the values of the eigenvectors:
PCA <- prcomp(dat1, center = T, scale = T)
PCA$rotation
PC1 PC2
atomic.no 0.7071068 0.7071068
melting.point 0.7071068 -0.7071068
As a final point, it is legitimate to wonder if, at the end of the day, we are simply doing ordinary least squares in a different way, using the eigenvectors to define hyperplanes through data clouds, because of the obvious similarities. To begin with the objective in both methods is different: PCA is meant to reduce dimensionality to understand the main drivers in the variability of datasets, whereas OLS is intended to extract the relationship between a "dependent" variable and one or multiple explanatory variables.
In the case of a single explanatory variable as in the toy example in this post, we can also superimpose the OLS regression line on the data cloud to note how OLS reduces the sum of vertical squared distances from the fitted line to the points, as opposed to orthogonal lines to the eigenvector in question:
In OLS the squared residuals are the hypothenuses of the perpendiculars from the points to the OLS line, and hence result in a higher sum of squared residuals (12.77) than the sum of the squared perpendicular segments from the points to the OLS line (11.74). The latter is what PCA is optimized for: (Wikipedia) "PCA quantifies data representation as the aggregate of the L2-norm of the data point projections into the subspace, or equivalently the aggregate Euclidean distance of the original points from their subspace-projected representations." This subspace has the orthogonal eigenvectors of the covariance matrix as a basis. The proof of this statement can be found here together with the pertinent credit to Marc Deisenroth.
Naturally, the fact that the dataset has been scaled and centered at zero, reduces the intercept of the OLS to zero, and the slope to the correlation between the variables, 0.2964.
This interactive tutorial by Victor Powell gives immediate feedback as to the changes in the eigenvectors as the data cloud is modified.
All the code related to this post can be found here. | Making sense of principal component analysis, eigenvectors & eigenvalues
After the excellent post by JD Long in this thread, I looked for a simple example, and the R code necessary to produce the PCA and then go back to the original data. It gave me some first-hand geometr |
11 | Making sense of principal component analysis, eigenvectors & eigenvalues | OK, a totally non-math answer:
If you have a bunch of variables on a bunch of subjects and you want to reduce it to a smaller number of variables on those same subjects, while losing as little information as possible, then PCA is one tool to do this.
It differs from factor analysis, although they often give similar results, in that FA tries to recover a small number of latent variables from a larger number of observed variables that are believed to be related to the latent variables. | Making sense of principal component analysis, eigenvectors & eigenvalues | OK, a totally non-math answer:
If you have a bunch of variables on a bunch of subjects and you want to reduce it to a smaller number of variables on those same subjects, while losing as little informa | Making sense of principal component analysis, eigenvectors & eigenvalues
OK, a totally non-math answer:
If you have a bunch of variables on a bunch of subjects and you want to reduce it to a smaller number of variables on those same subjects, while losing as little information as possible, then PCA is one tool to do this.
It differs from factor analysis, although they often give similar results, in that FA tries to recover a small number of latent variables from a larger number of observed variables that are believed to be related to the latent variables. | Making sense of principal component analysis, eigenvectors & eigenvalues
OK, a totally non-math answer:
If you have a bunch of variables on a bunch of subjects and you want to reduce it to a smaller number of variables on those same subjects, while losing as little informa |
12 | Making sense of principal component analysis, eigenvectors & eigenvalues | From someone who has used PCA a lot (and tried to explain it to a few people as well) here's an example from my own field of neuroscience.
When we're recording from a person's scalp we do it with 64 electrodes. So, in effect we have 64 numbers in a list that represent the voltage given off by the scalp. Now since we record with microsecond precision, if we have a 1-hour experiment (often they are 4 hours) then that gives us 1e6 * 60^2 == 3,600,000,000 time points at which a voltage was recorded at each electrode so that now we have a 3,600,000,000 x 64 matrix. Since a major assumption of PCA is that your variables are correlated, it is a great technique to reduce this ridiculous amount of data to an amount that is tractable. As has been said numerous times already, the eigenvalues represent the amount of variance explained by the variables (columns). In this case an eigenvalue represents the variance in the voltage at a particular point in time contributed by a particular electrode. So now we can say, "Oh, well electrode x at time point y is what we should focus on for further analysis because that is where the most change is happening". Hope this helps. Loving those regression plots! | Making sense of principal component analysis, eigenvectors & eigenvalues | From someone who has used PCA a lot (and tried to explain it to a few people as well) here's an example from my own field of neuroscience.
When we're recording from a person's scalp we do it with 64 e | Making sense of principal component analysis, eigenvectors & eigenvalues
From someone who has used PCA a lot (and tried to explain it to a few people as well) here's an example from my own field of neuroscience.
When we're recording from a person's scalp we do it with 64 electrodes. So, in effect we have 64 numbers in a list that represent the voltage given off by the scalp. Now since we record with microsecond precision, if we have a 1-hour experiment (often they are 4 hours) then that gives us 1e6 * 60^2 == 3,600,000,000 time points at which a voltage was recorded at each electrode so that now we have a 3,600,000,000 x 64 matrix. Since a major assumption of PCA is that your variables are correlated, it is a great technique to reduce this ridiculous amount of data to an amount that is tractable. As has been said numerous times already, the eigenvalues represent the amount of variance explained by the variables (columns). In this case an eigenvalue represents the variance in the voltage at a particular point in time contributed by a particular electrode. So now we can say, "Oh, well electrode x at time point y is what we should focus on for further analysis because that is where the most change is happening". Hope this helps. Loving those regression plots! | Making sense of principal component analysis, eigenvectors & eigenvalues
From someone who has used PCA a lot (and tried to explain it to a few people as well) here's an example from my own field of neuroscience.
When we're recording from a person's scalp we do it with 64 e |
13 | Making sense of principal component analysis, eigenvectors & eigenvalues | I might be a bad person to answer this because I'm the proverbial grandmother who has had the concept explained to me and not much more, but here goes:
Suppose you have a population. A large portion of the population is dropping dead of heart attacks. You are trying to figure out what causes the heart attacks.
You have two pieces of data: height and weight.
Now, it's clear that there's SOME relationship between weight and heart attacks, but the correlation isn't really strong. There are some heavy people who have a lot of heart attacks, but some don't.
Now, you do a PCA, and it tells you that weight divided by height ('body mass') is a much more likely predictor of heart attacks then either weight or height, because, lo and behold, the "reality" is that it's body mass that causes the heart attacks.
Essentially, you do PCA because you are measuring a bunch of things and you don't really know if those are really the principal components or if there's some deeper underlying component that you didn't measure.
[Please feel free to edit this if it's completely off base. I really don't understand the concept any more deeply than this]. | Making sense of principal component analysis, eigenvectors & eigenvalues | I might be a bad person to answer this because I'm the proverbial grandmother who has had the concept explained to me and not much more, but here goes:
Suppose you have a population. A large portion o | Making sense of principal component analysis, eigenvectors & eigenvalues
I might be a bad person to answer this because I'm the proverbial grandmother who has had the concept explained to me and not much more, but here goes:
Suppose you have a population. A large portion of the population is dropping dead of heart attacks. You are trying to figure out what causes the heart attacks.
You have two pieces of data: height and weight.
Now, it's clear that there's SOME relationship between weight and heart attacks, but the correlation isn't really strong. There are some heavy people who have a lot of heart attacks, but some don't.
Now, you do a PCA, and it tells you that weight divided by height ('body mass') is a much more likely predictor of heart attacks then either weight or height, because, lo and behold, the "reality" is that it's body mass that causes the heart attacks.
Essentially, you do PCA because you are measuring a bunch of things and you don't really know if those are really the principal components or if there's some deeper underlying component that you didn't measure.
[Please feel free to edit this if it's completely off base. I really don't understand the concept any more deeply than this]. | Making sense of principal component analysis, eigenvectors & eigenvalues
I might be a bad person to answer this because I'm the proverbial grandmother who has had the concept explained to me and not much more, but here goes:
Suppose you have a population. A large portion o |
14 | Making sense of principal component analysis, eigenvectors & eigenvalues | This answer gives an intuitive and not-mathematical interpretation:
The PCA will give you a set of orthogonal vectors within a high-dimensional point cloud. The order of the vectors is determined by the information conveyed aftter projecting all points onto the vectors.
In different words: The first principal component vector will tell you the most about the point cloud after projecting all points onto the vector. This is an intuitve interpretation of course.
Look at this ellipsoid (follow link for a 3D model):
If you would have to choose one vector forming a one-dimensional sub-space onto which the points of the ellipsoids points will be projected. Which one would you choose because it conveys the most information about the original set in 3 dimensions?
I guess the red one along the longest axis. And this is actually the calculated 1st principal component! Which one next - I would choose the blue one along the next longest axis.
Typically you want to project a set of points from a high-dimensional space onto a two dimensional plane or into a three dimensional space.
http://www.joyofdata.de/blog/illustration-of-principal-component-analysis-pca/ | Making sense of principal component analysis, eigenvectors & eigenvalues | This answer gives an intuitive and not-mathematical interpretation:
The PCA will give you a set of orthogonal vectors within a high-dimensional point cloud. The order of the vectors is determined by t | Making sense of principal component analysis, eigenvectors & eigenvalues
This answer gives an intuitive and not-mathematical interpretation:
The PCA will give you a set of orthogonal vectors within a high-dimensional point cloud. The order of the vectors is determined by the information conveyed aftter projecting all points onto the vectors.
In different words: The first principal component vector will tell you the most about the point cloud after projecting all points onto the vector. This is an intuitve interpretation of course.
Look at this ellipsoid (follow link for a 3D model):
If you would have to choose one vector forming a one-dimensional sub-space onto which the points of the ellipsoids points will be projected. Which one would you choose because it conveys the most information about the original set in 3 dimensions?
I guess the red one along the longest axis. And this is actually the calculated 1st principal component! Which one next - I would choose the blue one along the next longest axis.
Typically you want to project a set of points from a high-dimensional space onto a two dimensional plane or into a three dimensional space.
http://www.joyofdata.de/blog/illustration-of-principal-component-analysis-pca/ | Making sense of principal component analysis, eigenvectors & eigenvalues
This answer gives an intuitive and not-mathematical interpretation:
The PCA will give you a set of orthogonal vectors within a high-dimensional point cloud. The order of the vectors is determined by t |
15 | Making sense of principal component analysis, eigenvectors & eigenvalues | Here's one for Grandma:
In our town there are streets going north and south, some going east and west, and even some going northwest and southeast, some NE to SW. One day a guy measures all the traffic on all the streets, he finds that the most traffic is going diagonally, from northwest to southeast, the second biggest is perpendicular to this going northeast to southwest and all the rest is fairly small. So he draws a big square and puts a big line left to right and says that is the NW to SE, then draws another line vertically up and down through the middle. He says that's the second most crowded direction for traffic (NE to SW). The rest is small so it can be ignored.
The left right line is the first eigenvector and the up down line is the second eigenvector. The total number of cars going left and right are the first eigenvalue and those going up and down are the second eigenvalue. | Making sense of principal component analysis, eigenvectors & eigenvalues | Here's one for Grandma:
In our town there are streets going north and south, some going east and west, and even some going northwest and southeast, some NE to SW. One day a guy measures all the traffi | Making sense of principal component analysis, eigenvectors & eigenvalues
Here's one for Grandma:
In our town there are streets going north and south, some going east and west, and even some going northwest and southeast, some NE to SW. One day a guy measures all the traffic on all the streets, he finds that the most traffic is going diagonally, from northwest to southeast, the second biggest is perpendicular to this going northeast to southwest and all the rest is fairly small. So he draws a big square and puts a big line left to right and says that is the NW to SE, then draws another line vertically up and down through the middle. He says that's the second most crowded direction for traffic (NE to SW). The rest is small so it can be ignored.
The left right line is the first eigenvector and the up down line is the second eigenvector. The total number of cars going left and right are the first eigenvalue and those going up and down are the second eigenvalue. | Making sense of principal component analysis, eigenvectors & eigenvalues
Here's one for Grandma:
In our town there are streets going north and south, some going east and west, and even some going northwest and southeast, some NE to SW. One day a guy measures all the traffi |
16 | Making sense of principal component analysis, eigenvectors & eigenvalues | Although there are many examples given to provide an intuitive understanding of PCA, that fact can almost make it more difficult to grasp at the outset, at least it was for me.
"What was the one thing about PCA that all these different examples from different disciplines have in common??"
What helped me intuitively understand were a couple of math parallels, since it's apparent the maths is the easy part for you, although this doesn't help explain it to your grandmother...
Think of a regularization problem, trying to get
$$|| XB - Y || = 0$$
Or in English, break down your data $Y$ into two other matrices which will somehow shed light on the data? If those two matrices work well, then the error between them and $Y$ shouldn't be too much.
PCA gives you a useful factorizaton of $Y$, for all the reasons other people have said. It breaks the matrix of data you have, $Y$, down into two other useful matrices. In this case, $X$ would be a matrix where the columns are first $k$ PCs you kept, and $B$ is a matrix giving you a recipe to reconstruct the columns of matrix $Y$ using the columns of $X$. $B$ is the first $k$ rows of $S$, and all of $V$ transpose. The eigenvalues on the diagonal of $S$ basically weights which PCs are most important. That is how the math explicitly tells you which PCs are the most important: they are each weighted by their eigenvalues. Then, the matrix $V^\mathrm{T}$ tells the PCs how to combine.
I think people gave many intuitive examples, so I just wanted to share that. Seeing that helped me understand how it works. There are a world of interesting algorithms and methods which do similar things as PCA. Sparse coding is a subfield of machine learning which is all about factoring matrix $A$ into two other useful and interesting ones that reflect patterns in $A$. | Making sense of principal component analysis, eigenvectors & eigenvalues | Although there are many examples given to provide an intuitive understanding of PCA, that fact can almost make it more difficult to grasp at the outset, at least it was for me.
"What was the one thi | Making sense of principal component analysis, eigenvectors & eigenvalues
Although there are many examples given to provide an intuitive understanding of PCA, that fact can almost make it more difficult to grasp at the outset, at least it was for me.
"What was the one thing about PCA that all these different examples from different disciplines have in common??"
What helped me intuitively understand were a couple of math parallels, since it's apparent the maths is the easy part for you, although this doesn't help explain it to your grandmother...
Think of a regularization problem, trying to get
$$|| XB - Y || = 0$$
Or in English, break down your data $Y$ into two other matrices which will somehow shed light on the data? If those two matrices work well, then the error between them and $Y$ shouldn't be too much.
PCA gives you a useful factorizaton of $Y$, for all the reasons other people have said. It breaks the matrix of data you have, $Y$, down into two other useful matrices. In this case, $X$ would be a matrix where the columns are first $k$ PCs you kept, and $B$ is a matrix giving you a recipe to reconstruct the columns of matrix $Y$ using the columns of $X$. $B$ is the first $k$ rows of $S$, and all of $V$ transpose. The eigenvalues on the diagonal of $S$ basically weights which PCs are most important. That is how the math explicitly tells you which PCs are the most important: they are each weighted by their eigenvalues. Then, the matrix $V^\mathrm{T}$ tells the PCs how to combine.
I think people gave many intuitive examples, so I just wanted to share that. Seeing that helped me understand how it works. There are a world of interesting algorithms and methods which do similar things as PCA. Sparse coding is a subfield of machine learning which is all about factoring matrix $A$ into two other useful and interesting ones that reflect patterns in $A$. | Making sense of principal component analysis, eigenvectors & eigenvalues
Although there are many examples given to provide an intuitive understanding of PCA, that fact can almost make it more difficult to grasp at the outset, at least it was for me.
"What was the one thi |
17 | Making sense of principal component analysis, eigenvectors & eigenvalues | I'll give a non-mathy response and a more detailed birds-eye view of the motivation-through-math in the second part.
Non-Mathy:
The non-math explanation is that PCA helps for high dimensional data by letting you see in which directions your data has the most variance. These directions are the principal components. Once you have this information you can then, in some cases, decide to use the principal components as the meaningful variables themselves, and vastly reduce the dimensionality of your data by only keeping the principal components with the most variance (explanatory power).
For example, suppose you give out a political polling questionnaire with 30 questions, each can be given a response of 1 (strongly disagree) through 5 (strongly agree). You get tons of responses and now you have 30-dimensional data and you can't make heads or tails out of it. Then in desperation you think to run PCA and discover the 90% of your variance comes from one direction, and that direction does not correspond to any of your axis. After further inspection of the data you then conclude that this new hybrid axis corresponds to the political left-right spectrum i.e. democrat/republican spectrum, and go on to look at the more subtle aspects in the data.
Mathy:
It sometimes helps to zoom out and look at the mathematical motivation to shed some light on the meaning.
There is a special family of matrices which can be transformed into diagonal matrices simply by changing your coordinate axis. Naturally, they are called the diagonalizeable matrices and elegantly enough, the new coordinate axis that are needed to do this are indeed the eigenvectors.
As it turns out the covariance matrix are symmetric and will always be diagonalizeable! In this case the eigenvectors are called the principal components and when you write out the covariance matrix in eigenvector coordinates, the diagonal entries (the only ones left) correspond to the variance in the direction of your eigenvectors. This allows us to know which directions have the most variance. Moreover since the covariance matrix is diagonal in these coordinates, you have cleverly eliminated all correlation between your variables.
As is common in practical applications, we assume that our variables are normally distributed and so its quite natural to try and change our coordinates to see the simplest picture. By knowing your principal components and their respective eigenvalues (variance) you'll be able to reduce the dimensionality of your data if needed and also have a quick general summary of where the variation in your data lies.
But at the end of the day, the root of all this desirability comes from the fact that diagonal matrices are way easier to deal with in comparison to their messier, more general cousins. | Making sense of principal component analysis, eigenvectors & eigenvalues | I'll give a non-mathy response and a more detailed birds-eye view of the motivation-through-math in the second part.
Non-Mathy:
The non-math explanation is that PCA helps for high dimensional data b | Making sense of principal component analysis, eigenvectors & eigenvalues
I'll give a non-mathy response and a more detailed birds-eye view of the motivation-through-math in the second part.
Non-Mathy:
The non-math explanation is that PCA helps for high dimensional data by letting you see in which directions your data has the most variance. These directions are the principal components. Once you have this information you can then, in some cases, decide to use the principal components as the meaningful variables themselves, and vastly reduce the dimensionality of your data by only keeping the principal components with the most variance (explanatory power).
For example, suppose you give out a political polling questionnaire with 30 questions, each can be given a response of 1 (strongly disagree) through 5 (strongly agree). You get tons of responses and now you have 30-dimensional data and you can't make heads or tails out of it. Then in desperation you think to run PCA and discover the 90% of your variance comes from one direction, and that direction does not correspond to any of your axis. After further inspection of the data you then conclude that this new hybrid axis corresponds to the political left-right spectrum i.e. democrat/republican spectrum, and go on to look at the more subtle aspects in the data.
Mathy:
It sometimes helps to zoom out and look at the mathematical motivation to shed some light on the meaning.
There is a special family of matrices which can be transformed into diagonal matrices simply by changing your coordinate axis. Naturally, they are called the diagonalizeable matrices and elegantly enough, the new coordinate axis that are needed to do this are indeed the eigenvectors.
As it turns out the covariance matrix are symmetric and will always be diagonalizeable! In this case the eigenvectors are called the principal components and when you write out the covariance matrix in eigenvector coordinates, the diagonal entries (the only ones left) correspond to the variance in the direction of your eigenvectors. This allows us to know which directions have the most variance. Moreover since the covariance matrix is diagonal in these coordinates, you have cleverly eliminated all correlation between your variables.
As is common in practical applications, we assume that our variables are normally distributed and so its quite natural to try and change our coordinates to see the simplest picture. By knowing your principal components and their respective eigenvalues (variance) you'll be able to reduce the dimensionality of your data if needed and also have a quick general summary of where the variation in your data lies.
But at the end of the day, the root of all this desirability comes from the fact that diagonal matrices are way easier to deal with in comparison to their messier, more general cousins. | Making sense of principal component analysis, eigenvectors & eigenvalues
I'll give a non-mathy response and a more detailed birds-eye view of the motivation-through-math in the second part.
Non-Mathy:
The non-math explanation is that PCA helps for high dimensional data b |
18 | Making sense of principal component analysis, eigenvectors & eigenvalues | Here is a math answer: the first principal component is the longest dimension of the data. Look at it and ask: where is the data widest? That's the first component. The next component is the perpendicular. So a cigar of data has a length and a width. It makes sense for anything that is sort of oblong. | Making sense of principal component analysis, eigenvectors & eigenvalues | Here is a math answer: the first principal component is the longest dimension of the data. Look at it and ask: where is the data widest? That's the first component. The next component is the perpendic | Making sense of principal component analysis, eigenvectors & eigenvalues
Here is a math answer: the first principal component is the longest dimension of the data. Look at it and ask: where is the data widest? That's the first component. The next component is the perpendicular. So a cigar of data has a length and a width. It makes sense for anything that is sort of oblong. | Making sense of principal component analysis, eigenvectors & eigenvalues
Here is a math answer: the first principal component is the longest dimension of the data. Look at it and ask: where is the data widest? That's the first component. The next component is the perpendic |
19 | Making sense of principal component analysis, eigenvectors & eigenvalues | The way I understand principal components is this: Data with multiple variables (height, weight, age, temperature, wavelength, percent survival, etc) can be presented in three dimensions to plot relatedness.
Now if you wanted to somehow make sense of "3D data", you might want to know which 2D planes (cross-sections) of this 3D data contain the most information for a given suite of variables. These 2D planes are the principal components, which contain a proportion of each variable.
Think of principal components as variables themselves, with composite characteristics from the original variables (this new variable could be described as being part weight, part height, part age, etc). When you plot one principal component (X) against another (Y), what you're doing is building a 2D map that can geometrically describe correlations between original variables. Now the useful part: since each subject (observation) being compared is associated with values for each variable, the subjects (observations) are also found somewhere on this X Y map. Their location is based on the relative contributions of each underlying variable (i.e. one observation may be heavily affected by age and temperature, while another one may be more affected by height and weight). This map graphically shows us the similarities and differences between subjects and explains these similarities/differences in terms of which variables are characterizing them the most. | Making sense of principal component analysis, eigenvectors & eigenvalues | The way I understand principal components is this: Data with multiple variables (height, weight, age, temperature, wavelength, percent survival, etc) can be presented in three dimensions to plot relat | Making sense of principal component analysis, eigenvectors & eigenvalues
The way I understand principal components is this: Data with multiple variables (height, weight, age, temperature, wavelength, percent survival, etc) can be presented in three dimensions to plot relatedness.
Now if you wanted to somehow make sense of "3D data", you might want to know which 2D planes (cross-sections) of this 3D data contain the most information for a given suite of variables. These 2D planes are the principal components, which contain a proportion of each variable.
Think of principal components as variables themselves, with composite characteristics from the original variables (this new variable could be described as being part weight, part height, part age, etc). When you plot one principal component (X) against another (Y), what you're doing is building a 2D map that can geometrically describe correlations between original variables. Now the useful part: since each subject (observation) being compared is associated with values for each variable, the subjects (observations) are also found somewhere on this X Y map. Their location is based on the relative contributions of each underlying variable (i.e. one observation may be heavily affected by age and temperature, while another one may be more affected by height and weight). This map graphically shows us the similarities and differences between subjects and explains these similarities/differences in terms of which variables are characterizing them the most. | Making sense of principal component analysis, eigenvectors & eigenvalues
The way I understand principal components is this: Data with multiple variables (height, weight, age, temperature, wavelength, percent survival, etc) can be presented in three dimensions to plot relat |
20 | Making sense of principal component analysis, eigenvectors & eigenvalues | I view PCA as a geometric tool. If you are given a bunch of points in 3-space which are pretty much all on a straight line, and you want to figure out the equation of that line, you get it via PCA (take the first component). If you have a bunch of points in 3-space which are mostly planar, and want to discover the equation of that plane, do it via PCA (take the least significant component vector and that should be normal to the plane). | Making sense of principal component analysis, eigenvectors & eigenvalues | I view PCA as a geometric tool. If you are given a bunch of points in 3-space which are pretty much all on a straight line, and you want to figure out the equation of that line, you get it via PCA (ta | Making sense of principal component analysis, eigenvectors & eigenvalues
I view PCA as a geometric tool. If you are given a bunch of points in 3-space which are pretty much all on a straight line, and you want to figure out the equation of that line, you get it via PCA (take the first component). If you have a bunch of points in 3-space which are mostly planar, and want to discover the equation of that plane, do it via PCA (take the least significant component vector and that should be normal to the plane). | Making sense of principal component analysis, eigenvectors & eigenvalues
I view PCA as a geometric tool. If you are given a bunch of points in 3-space which are pretty much all on a straight line, and you want to figure out the equation of that line, you get it via PCA (ta |
21 | Making sense of principal component analysis, eigenvectors & eigenvalues | Why so eigenvalues/eigenvectors ?
When doing PCA, you want to compute some orthogonal basis by maximizing the projected variance on each basis vector.
Having computed previous basis vectors, you want the next one to be:
orthogonal to the previous
norm 1
maximizing projected variance, i.e with maximal covariance norm
This is a constrained optimization problem, and the Lagrange multipliers (here's for the geometric intuition, see wikipedia page) tell you that the gradients of the objective (projected variance) and the constraint (unit norm) should be "parallel" at the optimium.
This is the same as saying that the next basis vector should be an eigenvector of the covariance matrix. The best choice at each step is to pick the one with the largest eigenvalue among the remaining ones. | Making sense of principal component analysis, eigenvectors & eigenvalues | Why so eigenvalues/eigenvectors ?
When doing PCA, you want to compute some orthogonal basis by maximizing the projected variance on each basis vector.
Having computed previous basis vectors, you want | Making sense of principal component analysis, eigenvectors & eigenvalues
Why so eigenvalues/eigenvectors ?
When doing PCA, you want to compute some orthogonal basis by maximizing the projected variance on each basis vector.
Having computed previous basis vectors, you want the next one to be:
orthogonal to the previous
norm 1
maximizing projected variance, i.e with maximal covariance norm
This is a constrained optimization problem, and the Lagrange multipliers (here's for the geometric intuition, see wikipedia page) tell you that the gradients of the objective (projected variance) and the constraint (unit norm) should be "parallel" at the optimium.
This is the same as saying that the next basis vector should be an eigenvector of the covariance matrix. The best choice at each step is to pick the one with the largest eigenvalue among the remaining ones. | Making sense of principal component analysis, eigenvectors & eigenvalues
Why so eigenvalues/eigenvectors ?
When doing PCA, you want to compute some orthogonal basis by maximizing the projected variance on each basis vector.
Having computed previous basis vectors, you want |
22 | Making sense of principal component analysis, eigenvectors & eigenvalues | Some time back I tried to understand this PCA algorithm and I wanted to make a note about eigen vectors and eigen values. That document stated that the purpose of EVs is to convert a model of the large sized model to a very small sized model.
For example, instead of constructing first the full sized bridge and then carrying out experiments and tests on it, it is possible to use EVs to create a very small sized bridge where all the factors/quantities will be reduced by the same margin and moreover the actual result of tests and stress related tests carried out on it can be calculated and enlarged appropriately as needed for the original model. In a way EVs help to create abstracts of the original.
To me, this explaination had profound meaning to what I was trying to do! Hope it helps you too! | Making sense of principal component analysis, eigenvectors & eigenvalues | Some time back I tried to understand this PCA algorithm and I wanted to make a note about eigen vectors and eigen values. That document stated that the purpose of EVs is to convert a model of the larg | Making sense of principal component analysis, eigenvectors & eigenvalues
Some time back I tried to understand this PCA algorithm and I wanted to make a note about eigen vectors and eigen values. That document stated that the purpose of EVs is to convert a model of the large sized model to a very small sized model.
For example, instead of constructing first the full sized bridge and then carrying out experiments and tests on it, it is possible to use EVs to create a very small sized bridge where all the factors/quantities will be reduced by the same margin and moreover the actual result of tests and stress related tests carried out on it can be calculated and enlarged appropriately as needed for the original model. In a way EVs help to create abstracts of the original.
To me, this explaination had profound meaning to what I was trying to do! Hope it helps you too! | Making sense of principal component analysis, eigenvectors & eigenvalues
Some time back I tried to understand this PCA algorithm and I wanted to make a note about eigen vectors and eigen values. That document stated that the purpose of EVs is to convert a model of the larg |
23 | Making sense of principal component analysis, eigenvectors & eigenvalues | Imagine grandma has just taken her first photos and movies on the digital camera you gave her for Christmas, unfortunately she drops her right hand as she pushes down on the button for photos, and she shakes quite a bit during the movies too. She notices that the people, trees, fences, buildings, doorways, furniture, etc. aren't straight up and down, aren't vertical, and that the floor, the ground, the sea, the horizon isn't well horizontal, and well the movies are rather shaky as well. She asks if you can you help her fix them, all 3000 holiday photos and about 100 videos at home and beach (she's Australian), opening presents, walking in the country. She's got this photo software that allows you to do that she says. You tell her that that would take days, and won't work on the videos anyway, but you know techniques called PCA and ICA that might help. You explain that your research actually involves just this kind of rotation of data into the natural dimensions, that these techniques find the most important directions in the data, the photo in this case, and rotate so the most important one is horizontal, the second one is vertical (and it can even go on for more dimensions we can't imagine very well, although time is also a dimension in the movies).
--
Technical Aside. In fact, you could probably earn your PhD doing this for her, and there is an important paper by Bell and Sejnowski (1997) about independent components of images corresponding to edges. To relate this to PCA: ICA uses PCA or SVD as a first step to reduce the dimensionality and initial approximations, but then improves them that takes into account not only second order error (SSE) like PCA, but high order errors - if it's true ICA, all higher orders, although many algorithms confine themselves to 3rd or 4th. The low order PCA components do tend to be influenced strongly by the horizontals and verticals. Dealing with camera motion for the movies can also make use of PCA/ICA. Both for the 2D photos and the 2½D movies you need a couple of representational tricks to achieve this.
Another application you could explain to grandma is eigenfaces - higher order eigenvectors can approximate the '7 basic emotions' (the average face for each of them and the 'scaled rotation' or linear combination to do that averaging), but often we find components that are sex and race related, and some might distinguish individuals or individual features (glasses, beard, etc.). This is what happens if you have few photos of any one individual and many emotions/expressions, but you get a different bias if you have many faces with neutral expressions. Using ICA instead of PCA doesn't really seem to help much for basic emotions, but Bartlett and Sejnowsiki (1997) showed it found useful features for face recognition. | Making sense of principal component analysis, eigenvectors & eigenvalues | Imagine grandma has just taken her first photos and movies on the digital camera you gave her for Christmas, unfortunately she drops her right hand as she pushes down on the button for photos, and she | Making sense of principal component analysis, eigenvectors & eigenvalues
Imagine grandma has just taken her first photos and movies on the digital camera you gave her for Christmas, unfortunately she drops her right hand as she pushes down on the button for photos, and she shakes quite a bit during the movies too. She notices that the people, trees, fences, buildings, doorways, furniture, etc. aren't straight up and down, aren't vertical, and that the floor, the ground, the sea, the horizon isn't well horizontal, and well the movies are rather shaky as well. She asks if you can you help her fix them, all 3000 holiday photos and about 100 videos at home and beach (she's Australian), opening presents, walking in the country. She's got this photo software that allows you to do that she says. You tell her that that would take days, and won't work on the videos anyway, but you know techniques called PCA and ICA that might help. You explain that your research actually involves just this kind of rotation of data into the natural dimensions, that these techniques find the most important directions in the data, the photo in this case, and rotate so the most important one is horizontal, the second one is vertical (and it can even go on for more dimensions we can't imagine very well, although time is also a dimension in the movies).
--
Technical Aside. In fact, you could probably earn your PhD doing this for her, and there is an important paper by Bell and Sejnowski (1997) about independent components of images corresponding to edges. To relate this to PCA: ICA uses PCA or SVD as a first step to reduce the dimensionality and initial approximations, but then improves them that takes into account not only second order error (SSE) like PCA, but high order errors - if it's true ICA, all higher orders, although many algorithms confine themselves to 3rd or 4th. The low order PCA components do tend to be influenced strongly by the horizontals and verticals. Dealing with camera motion for the movies can also make use of PCA/ICA. Both for the 2D photos and the 2½D movies you need a couple of representational tricks to achieve this.
Another application you could explain to grandma is eigenfaces - higher order eigenvectors can approximate the '7 basic emotions' (the average face for each of them and the 'scaled rotation' or linear combination to do that averaging), but often we find components that are sex and race related, and some might distinguish individuals or individual features (glasses, beard, etc.). This is what happens if you have few photos of any one individual and many emotions/expressions, but you get a different bias if you have many faces with neutral expressions. Using ICA instead of PCA doesn't really seem to help much for basic emotions, but Bartlett and Sejnowsiki (1997) showed it found useful features for face recognition. | Making sense of principal component analysis, eigenvectors & eigenvalues
Imagine grandma has just taken her first photos and movies on the digital camera you gave her for Christmas, unfortunately she drops her right hand as she pushes down on the button for photos, and she |
24 | Making sense of principal component analysis, eigenvectors & eigenvalues | Basically PCA finds new variables which are linear combinations of the original variables such that in the new space, the data has fewer dimensions. Think of a data set consisting of the points in 3 dimensions on the surface of a flat plate held up at an angle. In the original x, y, z axes you need 3 dimensions to represent the data, but with the right linear transformation, you only need 2.
Basically what @Joel said, but only linear combinations of the input variables. | Making sense of principal component analysis, eigenvectors & eigenvalues | Basically PCA finds new variables which are linear combinations of the original variables such that in the new space, the data has fewer dimensions. Think of a data set consisting of the points in 3 | Making sense of principal component analysis, eigenvectors & eigenvalues
Basically PCA finds new variables which are linear combinations of the original variables such that in the new space, the data has fewer dimensions. Think of a data set consisting of the points in 3 dimensions on the surface of a flat plate held up at an angle. In the original x, y, z axes you need 3 dimensions to represent the data, but with the right linear transformation, you only need 2.
Basically what @Joel said, but only linear combinations of the input variables. | Making sense of principal component analysis, eigenvectors & eigenvalues
Basically PCA finds new variables which are linear combinations of the original variables such that in the new space, the data has fewer dimensions. Think of a data set consisting of the points in 3 |
25 | Making sense of principal component analysis, eigenvectors & eigenvalues | I think that everyone starts explaining PCA from the wrong end: from eigenvectors. My answer starts at the right place: coordinate system. Eigenvectors, and eigenproblem in general, are the mathematical tool that is used to address the real issue at hand which is a wrong coordinate system. I'll explain.
Let's start with a line. What is a line? It's a one dimensional object. So, you need only one dimension to move from one point to another. On a plane though you attach two coordinates to any point of a line.
That is because with respect to a line itself the coordinate system is chosen arbitrarily. Take a look at this line.
Does it look like a different object than the previous line? It may, if you keep looking at the coordinate. However, if you forget about the coordinate system, and just look at it as a geometrical object in space, then these two lines are identical!
The coordinate system, I would argue, does not reflect the inner one dimensional nature of the line. If only I would always put the origin of my Cartesian coordinate system on the line, and turned it so that its x-axis was on the line, then I would not need y-axis anymore! All my points are on one axis, because a line is a one dimensional object.
That's where PCA explanations should start. The eigen problem is a tool that does the rotation which I described, plus de-meaning of variables puts the origin onto the line. PCA helps reveal true dimensions of the data so long the relationships between the variables are linear. | Making sense of principal component analysis, eigenvectors & eigenvalues | I think that everyone starts explaining PCA from the wrong end: from eigenvectors. My answer starts at the right place: coordinate system. Eigenvectors, and eigenproblem in general, are the mathematic | Making sense of principal component analysis, eigenvectors & eigenvalues
I think that everyone starts explaining PCA from the wrong end: from eigenvectors. My answer starts at the right place: coordinate system. Eigenvectors, and eigenproblem in general, are the mathematical tool that is used to address the real issue at hand which is a wrong coordinate system. I'll explain.
Let's start with a line. What is a line? It's a one dimensional object. So, you need only one dimension to move from one point to another. On a plane though you attach two coordinates to any point of a line.
That is because with respect to a line itself the coordinate system is chosen arbitrarily. Take a look at this line.
Does it look like a different object than the previous line? It may, if you keep looking at the coordinate. However, if you forget about the coordinate system, and just look at it as a geometrical object in space, then these two lines are identical!
The coordinate system, I would argue, does not reflect the inner one dimensional nature of the line. If only I would always put the origin of my Cartesian coordinate system on the line, and turned it so that its x-axis was on the line, then I would not need y-axis anymore! All my points are on one axis, because a line is a one dimensional object.
That's where PCA explanations should start. The eigen problem is a tool that does the rotation which I described, plus de-meaning of variables puts the origin onto the line. PCA helps reveal true dimensions of the data so long the relationships between the variables are linear. | Making sense of principal component analysis, eigenvectors & eigenvalues
I think that everyone starts explaining PCA from the wrong end: from eigenvectors. My answer starts at the right place: coordinate system. Eigenvectors, and eigenproblem in general, are the mathematic |
26 | Making sense of principal component analysis, eigenvectors & eigenvalues | Remember that an eigenvector is a vector whose transform is parallel to the same input vector. Thus an eigenvector with a high eigenvalue means that the eigenvector has a high degree of 'parallelity' to the data, meaning that you can represent the data with this vector only and expect a low error in the new representation. If you pick additional eigenvectors with lower eigenvalues, you will be able to represent more details of the data because you'll be representing other 'parallelities' - which are not as prominent as the first one because of lower eigenvalues. | Making sense of principal component analysis, eigenvectors & eigenvalues | Remember that an eigenvector is a vector whose transform is parallel to the same input vector. Thus an eigenvector with a high eigenvalue means that the eigenvector has a high degree of 'parallelity' | Making sense of principal component analysis, eigenvectors & eigenvalues
Remember that an eigenvector is a vector whose transform is parallel to the same input vector. Thus an eigenvector with a high eigenvalue means that the eigenvector has a high degree of 'parallelity' to the data, meaning that you can represent the data with this vector only and expect a low error in the new representation. If you pick additional eigenvectors with lower eigenvalues, you will be able to represent more details of the data because you'll be representing other 'parallelities' - which are not as prominent as the first one because of lower eigenvalues. | Making sense of principal component analysis, eigenvectors & eigenvalues
Remember that an eigenvector is a vector whose transform is parallel to the same input vector. Thus an eigenvector with a high eigenvalue means that the eigenvector has a high degree of 'parallelity' |
27 | Making sense of principal component analysis, eigenvectors & eigenvalues | PCA basically is a projection of a higher-dimensional space into a lower dimensional space while preserving as much information as possible.
I wrote a blog post where I explain PCA via the projection of a 3D-teapot...
...onto a 2D-plane while preserving as much information as possible:
Details and full R-code can be found in the post:
http://blog.ephorie.de/intuition-for-principal-component-analysis-pca | Making sense of principal component analysis, eigenvectors & eigenvalues | PCA basically is a projection of a higher-dimensional space into a lower dimensional space while preserving as much information as possible.
I wrote a blog post where I explain PCA via the projection | Making sense of principal component analysis, eigenvectors & eigenvalues
PCA basically is a projection of a higher-dimensional space into a lower dimensional space while preserving as much information as possible.
I wrote a blog post where I explain PCA via the projection of a 3D-teapot...
...onto a 2D-plane while preserving as much information as possible:
Details and full R-code can be found in the post:
http://blog.ephorie.de/intuition-for-principal-component-analysis-pca | Making sense of principal component analysis, eigenvectors & eigenvalues
PCA basically is a projection of a higher-dimensional space into a lower dimensional space while preserving as much information as possible.
I wrote a blog post where I explain PCA via the projection |
28 | How to choose the number of hidden layers and nodes in a feedforward neural network? | I realize this question has been answered, but I don't think the extant answer really engages the question beyond pointing to a link generally related to the question's subject matter. In particular, the link describes one technique for programmatic network configuration, but that is not a "[a] standard and accepted method" for network configuration.
By following a small set of clear rules, one can programmatically set a competent network architecture (i.e., the number and type of neuronal layers and the number of neurons comprising each layer). Following this schema will give you a competent architecture but probably not an optimal one.
But once this network is initialized, you can iteratively tune the configuration during training using a number of ancillary algorithms; one family of these works by pruning nodes based on (small) values of the weight vector after a certain number of training epochs--in other words, eliminating unnecessary/redundant nodes (more on this below).
So every NN has three types of layers: input, hidden, and output.
Creating the NN architecture, therefore, means coming up with values for the number of layers of each type and the number of nodes in each of these layers.
The Input Layer
Simple--every NN has exactly one of them--no exceptions that I'm aware of.
With respect to the number of neurons comprising this layer, this parameter is completely and uniquely determined once you know the shape of your training data. Specifically, the number of neurons comprising that layer is equal to the number of features (columns) in your data. Some NN configurations add one additional node for a bias term.
The Output Layer
Like the Input layer, every NN has exactly one output layer. Determining its size (number of neurons) is simple; it is completely determined by the chosen model configuration.
Is your NN going to run in Machine Mode or Regression Mode (the ML convention of using a term that is also used in statistics but assigning a different meaning to it is very confusing)? Machine mode: returns a class label (e.g., "Premium Account"/"Basic Account"). Regression Mode returns a value (e.g., price).
If the NN is a regressor, then the output layer has a single node.
If the NN is a classifier, then it also has a single node unless softmax is used
in which case the output layer has one node per class label in your model.
The Hidden Layers
So those few rules set the number of layers and size (neurons/layer) for both the input and output layers. That leaves the hidden layers.
How many hidden layers? Well, if your data is linearly separable (which you often know by the time you begin coding a NN), then you don't need any hidden layers at all. Of course, you don't need an NN to resolve your data either, but it will still do the job.
Beyond that, as you probably know, there's a mountain of commentary on the question of hidden layer configuration in NNs (see the insanely thorough and insightful NN FAQ for an excellent summary of that commentary). One issue within this subject on which there is a consensus is the performance difference from adding additional hidden layers: the situations in which performance improves with a second (or third, etc.) hidden layer are very few. One hidden layer is sufficient for the large majority of problems.
So what about the size of the hidden layer(s)--how many neurons? There are some empirically derived rules of thumb; of these, the most commonly relied on is 'the optimal size of the hidden layer is usually between the size of the input and size of the output layers'. Jeff Heaton, the author of Introduction to Neural Networks in Java, offers a few more.
In sum, for most problems, one could probably get decent performance (even without a second optimization step) by setting the hidden layer configuration using just two rules: (i) the number of hidden layers equals one; and (ii) the number of neurons in that layer is the mean of the neurons in the input and output layers.
Optimization of the Network Configuration
Pruning describes a set of techniques to trim network size (by nodes, not layers) to improve computational performance and sometimes resolution performance. The gist of these techniques is removing nodes from the network during training by identifying those nodes which, if removed from the network, would not noticeably affect network performance (i.e., resolution of the data). (Even without using a formal pruning technique, you can get a rough idea of which nodes are not important by looking at your weight matrix after training; look at weights very close to zero--it's the nodes on either end of those weights that are often removed during pruning.) Obviously, if you use a pruning algorithm during training, then begin with a network configuration that is more likely to have excess (i.e., 'prunable') nodes--in other words, when deciding on network architecture, err on the side of more neurons, if you add a pruning step.
Put another way, by applying a pruning algorithm to your network during training, you can approach optimal network configuration; whether you can do that in a single "up-front" (such as a genetic-algorithm-based algorithm), I don't know, though I do know that for now, this two-step optimization is more common. | How to choose the number of hidden layers and nodes in a feedforward neural network? | I realize this question has been answered, but I don't think the extant answer really engages the question beyond pointing to a link generally related to the question's subject matter. In particular, | How to choose the number of hidden layers and nodes in a feedforward neural network?
I realize this question has been answered, but I don't think the extant answer really engages the question beyond pointing to a link generally related to the question's subject matter. In particular, the link describes one technique for programmatic network configuration, but that is not a "[a] standard and accepted method" for network configuration.
By following a small set of clear rules, one can programmatically set a competent network architecture (i.e., the number and type of neuronal layers and the number of neurons comprising each layer). Following this schema will give you a competent architecture but probably not an optimal one.
But once this network is initialized, you can iteratively tune the configuration during training using a number of ancillary algorithms; one family of these works by pruning nodes based on (small) values of the weight vector after a certain number of training epochs--in other words, eliminating unnecessary/redundant nodes (more on this below).
So every NN has three types of layers: input, hidden, and output.
Creating the NN architecture, therefore, means coming up with values for the number of layers of each type and the number of nodes in each of these layers.
The Input Layer
Simple--every NN has exactly one of them--no exceptions that I'm aware of.
With respect to the number of neurons comprising this layer, this parameter is completely and uniquely determined once you know the shape of your training data. Specifically, the number of neurons comprising that layer is equal to the number of features (columns) in your data. Some NN configurations add one additional node for a bias term.
The Output Layer
Like the Input layer, every NN has exactly one output layer. Determining its size (number of neurons) is simple; it is completely determined by the chosen model configuration.
Is your NN going to run in Machine Mode or Regression Mode (the ML convention of using a term that is also used in statistics but assigning a different meaning to it is very confusing)? Machine mode: returns a class label (e.g., "Premium Account"/"Basic Account"). Regression Mode returns a value (e.g., price).
If the NN is a regressor, then the output layer has a single node.
If the NN is a classifier, then it also has a single node unless softmax is used
in which case the output layer has one node per class label in your model.
The Hidden Layers
So those few rules set the number of layers and size (neurons/layer) for both the input and output layers. That leaves the hidden layers.
How many hidden layers? Well, if your data is linearly separable (which you often know by the time you begin coding a NN), then you don't need any hidden layers at all. Of course, you don't need an NN to resolve your data either, but it will still do the job.
Beyond that, as you probably know, there's a mountain of commentary on the question of hidden layer configuration in NNs (see the insanely thorough and insightful NN FAQ for an excellent summary of that commentary). One issue within this subject on which there is a consensus is the performance difference from adding additional hidden layers: the situations in which performance improves with a second (or third, etc.) hidden layer are very few. One hidden layer is sufficient for the large majority of problems.
So what about the size of the hidden layer(s)--how many neurons? There are some empirically derived rules of thumb; of these, the most commonly relied on is 'the optimal size of the hidden layer is usually between the size of the input and size of the output layers'. Jeff Heaton, the author of Introduction to Neural Networks in Java, offers a few more.
In sum, for most problems, one could probably get decent performance (even without a second optimization step) by setting the hidden layer configuration using just two rules: (i) the number of hidden layers equals one; and (ii) the number of neurons in that layer is the mean of the neurons in the input and output layers.
Optimization of the Network Configuration
Pruning describes a set of techniques to trim network size (by nodes, not layers) to improve computational performance and sometimes resolution performance. The gist of these techniques is removing nodes from the network during training by identifying those nodes which, if removed from the network, would not noticeably affect network performance (i.e., resolution of the data). (Even without using a formal pruning technique, you can get a rough idea of which nodes are not important by looking at your weight matrix after training; look at weights very close to zero--it's the nodes on either end of those weights that are often removed during pruning.) Obviously, if you use a pruning algorithm during training, then begin with a network configuration that is more likely to have excess (i.e., 'prunable') nodes--in other words, when deciding on network architecture, err on the side of more neurons, if you add a pruning step.
Put another way, by applying a pruning algorithm to your network during training, you can approach optimal network configuration; whether you can do that in a single "up-front" (such as a genetic-algorithm-based algorithm), I don't know, though I do know that for now, this two-step optimization is more common. | How to choose the number of hidden layers and nodes in a feedforward neural network?
I realize this question has been answered, but I don't think the extant answer really engages the question beyond pointing to a link generally related to the question's subject matter. In particular, |
29 | How to choose the number of hidden layers and nodes in a feedforward neural network? | @doug's answer has worked for me. There's one additional rule of thumb that helps for supervised learning problems. You can usually prevent over-fitting if you keep your number of neurons below:
$$N_h = \frac{N_s} {(\alpha * (N_i + N_o))}$$
$N_i$ = number of input neurons.
$N_o$ = number of output neurons.
$N_s$ = number of samples in training data set.
$\alpha$ = an arbitrary scaling factor usually 2-10.
Others recommend setting $\alpha$ to a value between 5 and 10, but I find a value of 2 will often work without overfitting. You can think of $\alpha$ as the effective branching factor or number of nonzero weights for each neuron. Dropout layers will bring the "effective" branching factor way down from the actual mean branching factor for your network.
As explained by this excellent NN Design text, you want to limit the number of free parameters in your model (its degree or number of nonzero weights) to a small portion of the degrees of freedom in your data. The degrees of freedom in your data is the number samples * degrees of freedom (dimensions) in each sample or $N_s * (N_i + N_o)$ (assuming they're all independent). So $\alpha$ is a way to indicate how general you want your model to be, or how much you want to prevent overfitting.
For an automated procedure you'd start with an $\alpha$ of 2 (twice as many degrees of freedom in your training data as your model) and work your way up to 10 if the error (loss) for your training dataset is significantly smaller than for your test dataset. | How to choose the number of hidden layers and nodes in a feedforward neural network? | @doug's answer has worked for me. There's one additional rule of thumb that helps for supervised learning problems. You can usually prevent over-fitting if you keep your number of neurons below:
$$N_h | How to choose the number of hidden layers and nodes in a feedforward neural network?
@doug's answer has worked for me. There's one additional rule of thumb that helps for supervised learning problems. You can usually prevent over-fitting if you keep your number of neurons below:
$$N_h = \frac{N_s} {(\alpha * (N_i + N_o))}$$
$N_i$ = number of input neurons.
$N_o$ = number of output neurons.
$N_s$ = number of samples in training data set.
$\alpha$ = an arbitrary scaling factor usually 2-10.
Others recommend setting $\alpha$ to a value between 5 and 10, but I find a value of 2 will often work without overfitting. You can think of $\alpha$ as the effective branching factor or number of nonzero weights for each neuron. Dropout layers will bring the "effective" branching factor way down from the actual mean branching factor for your network.
As explained by this excellent NN Design text, you want to limit the number of free parameters in your model (its degree or number of nonzero weights) to a small portion of the degrees of freedom in your data. The degrees of freedom in your data is the number samples * degrees of freedom (dimensions) in each sample or $N_s * (N_i + N_o)$ (assuming they're all independent). So $\alpha$ is a way to indicate how general you want your model to be, or how much you want to prevent overfitting.
For an automated procedure you'd start with an $\alpha$ of 2 (twice as many degrees of freedom in your training data as your model) and work your way up to 10 if the error (loss) for your training dataset is significantly smaller than for your test dataset. | How to choose the number of hidden layers and nodes in a feedforward neural network?
@doug's answer has worked for me. There's one additional rule of thumb that helps for supervised learning problems. You can usually prevent over-fitting if you keep your number of neurons below:
$$N_h |
30 | How to choose the number of hidden layers and nodes in a feedforward neural network? | From Introduction to Neural Networks for Java (second edition) by Jeff Heaton - preview freely available at Google Books and previously at author's website:
The Number of Hidden Layers
There are really two decisions that must be made regarding the hidden layers: how many hidden layers to actually have in the neural network and how many neurons will be in each of these layers. We will first examine how to determine the number of hidden layers to use with the neural network.
Problems that require two hidden layers are rarely encountered.
However, neural networks with two hidden layers can represent
functions with any kind of shape. There is currently no theoretical
reason to use neural networks with any more than two hidden layers. In
fact, for many practical problems, there is no reason to use any more
than one hidden layer. Table 5.1 summarizes the capabilities of neural
network architectures with various hidden layers.
Table 5.1: Determining the Number of Hidden Layers
| Number of Hidden Layers | Result |
0 - Only capable of representing linear separable functions or decisions.
1 - Can approximate any function that contains a continuous mapping
from one finite space to another.
2 - Can represent an arbitrary decision boundary to arbitrary accuracy
with rational activation functions and can approximate any smooth
mapping to any accuracy.
Deciding the number of hidden neuron layers is only a small part of
the problem. You must also determine how many neurons will be in each
of these hidden layers. This process is covered in the next section.
The Number of Neurons in the Hidden Layers
Deciding the number of neurons in the hidden layers is a very important part of deciding your
overall neural network architecture. Though these layers do not
directly interact with the external environment, they have a
tremendous influence on the final output. Both the number of hidden
layers and the number of neurons in each of these hidden layers must
be carefully considered.
Using too few neurons in the hidden layers will result in something
called underfitting. Underfitting occurs when there are too few
neurons in the hidden layers to adequately detect the signals in a
complicated data set.
Using too many neurons in the hidden layers can result in several
problems. First, too many neurons in the hidden layers may result in
overfitting. Overfitting occurs when the neural network has so much
information processing capacity that the limited amount of information
contained in the training set is not enough to train all of the
neurons in the hidden layers. A second problem can occur even when the
training data is sufficient. An inordinately large number of neurons
in the hidden layers can increase the time it takes to train the
network. The amount of training time can increase to the point that it
is impossible to adequately train the neural network. Obviously, some
compromise must be reached between too many and too few neurons in the
hidden layers.
There are many rule-of-thumb methods for determining the correct
number of neurons to use in the hidden layers, such as the following:
The number of hidden neurons should be between the size of the input
layer and the size of the output layer.
The number of hidden neurons should be 2/3 the size of the input layer, plus the size of the output layer.
The number of hidden neurons should be less than twice the size of the input layer.
These three rules provide a starting point for you
to consider. Ultimately, the selection of an architecture for your
neural network will come down to trial and error. But what exactly is
meant by trial and error? You do not want to start throwing random
numbers of layers and neurons at your network. To do so would be very
time consuming. Chapter 8, “Pruning a Neural Network” will explore
various ways to determine an optimal structure for a neural network.
I also like the following snippet from an answer I found at researchgate.net, which conveys a lot in just a few words:
Steffen B Petersen · Aalborg University
[...]
In order to secure the ability of the network to
generalize the number of nodes has to be kept as low as possible. If
you have a large excess of nodes, you network becomes a memory bank
that can recall the training set to perfection, but does not perform
well on samples that was not part of the training set. | How to choose the number of hidden layers and nodes in a feedforward neural network? | From Introduction to Neural Networks for Java (second edition) by Jeff Heaton - preview freely available at Google Books and previously at author's website:
The Number of Hidden Layers
There are r | How to choose the number of hidden layers and nodes in a feedforward neural network?
From Introduction to Neural Networks for Java (second edition) by Jeff Heaton - preview freely available at Google Books and previously at author's website:
The Number of Hidden Layers
There are really two decisions that must be made regarding the hidden layers: how many hidden layers to actually have in the neural network and how many neurons will be in each of these layers. We will first examine how to determine the number of hidden layers to use with the neural network.
Problems that require two hidden layers are rarely encountered.
However, neural networks with two hidden layers can represent
functions with any kind of shape. There is currently no theoretical
reason to use neural networks with any more than two hidden layers. In
fact, for many practical problems, there is no reason to use any more
than one hidden layer. Table 5.1 summarizes the capabilities of neural
network architectures with various hidden layers.
Table 5.1: Determining the Number of Hidden Layers
| Number of Hidden Layers | Result |
0 - Only capable of representing linear separable functions or decisions.
1 - Can approximate any function that contains a continuous mapping
from one finite space to another.
2 - Can represent an arbitrary decision boundary to arbitrary accuracy
with rational activation functions and can approximate any smooth
mapping to any accuracy.
Deciding the number of hidden neuron layers is only a small part of
the problem. You must also determine how many neurons will be in each
of these hidden layers. This process is covered in the next section.
The Number of Neurons in the Hidden Layers
Deciding the number of neurons in the hidden layers is a very important part of deciding your
overall neural network architecture. Though these layers do not
directly interact with the external environment, they have a
tremendous influence on the final output. Both the number of hidden
layers and the number of neurons in each of these hidden layers must
be carefully considered.
Using too few neurons in the hidden layers will result in something
called underfitting. Underfitting occurs when there are too few
neurons in the hidden layers to adequately detect the signals in a
complicated data set.
Using too many neurons in the hidden layers can result in several
problems. First, too many neurons in the hidden layers may result in
overfitting. Overfitting occurs when the neural network has so much
information processing capacity that the limited amount of information
contained in the training set is not enough to train all of the
neurons in the hidden layers. A second problem can occur even when the
training data is sufficient. An inordinately large number of neurons
in the hidden layers can increase the time it takes to train the
network. The amount of training time can increase to the point that it
is impossible to adequately train the neural network. Obviously, some
compromise must be reached between too many and too few neurons in the
hidden layers.
There are many rule-of-thumb methods for determining the correct
number of neurons to use in the hidden layers, such as the following:
The number of hidden neurons should be between the size of the input
layer and the size of the output layer.
The number of hidden neurons should be 2/3 the size of the input layer, plus the size of the output layer.
The number of hidden neurons should be less than twice the size of the input layer.
These three rules provide a starting point for you
to consider. Ultimately, the selection of an architecture for your
neural network will come down to trial and error. But what exactly is
meant by trial and error? You do not want to start throwing random
numbers of layers and neurons at your network. To do so would be very
time consuming. Chapter 8, “Pruning a Neural Network” will explore
various ways to determine an optimal structure for a neural network.
I also like the following snippet from an answer I found at researchgate.net, which conveys a lot in just a few words:
Steffen B Petersen · Aalborg University
[...]
In order to secure the ability of the network to
generalize the number of nodes has to be kept as low as possible. If
you have a large excess of nodes, you network becomes a memory bank
that can recall the training set to perfection, but does not perform
well on samples that was not part of the training set. | How to choose the number of hidden layers and nodes in a feedforward neural network?
From Introduction to Neural Networks for Java (second edition) by Jeff Heaton - preview freely available at Google Books and previously at author's website:
The Number of Hidden Layers
There are r |
31 | How to choose the number of hidden layers and nodes in a feedforward neural network? | I am working on an empirical study of this at the moment (approching a processor-century of simulations on our HPC facility!). My advice would be to use a "large" network and regularisation, if you use regularisation then the network architecture becomes less important (provided it is large enough to represent the underlying function we want to capture), but you do need to tune the regularisation parameter properly.
One of the problems with architecture selection is that it is a discrete, rather than continuous, control of the complexity of the model, and therefore can be a bit of a blunt instrument, especially when the ideal complexity is low.
However, this is all subject to the "no free lunch" theorems, while regularisation is effective in most cases, there will always be cases where architecture selection works better, and the only way to find out if that is true of the problem at hand is to try both approaches and cross-validate.
If I were to build an automated neural network builder, I would use Radford Neal's Hybrid Monte Carlo (HMC) sampling-based Bayesian approach, and use a large network and integrate over the weights rather than optimise the weights of a single network. However that is computationally expensive and a bit of a "black art", but the results Prof. Neal achieves suggests it is worth it! | How to choose the number of hidden layers and nodes in a feedforward neural network? | I am working on an empirical study of this at the moment (approching a processor-century of simulations on our HPC facility!). My advice would be to use a "large" network and regularisation, if you u | How to choose the number of hidden layers and nodes in a feedforward neural network?
I am working on an empirical study of this at the moment (approching a processor-century of simulations on our HPC facility!). My advice would be to use a "large" network and regularisation, if you use regularisation then the network architecture becomes less important (provided it is large enough to represent the underlying function we want to capture), but you do need to tune the regularisation parameter properly.
One of the problems with architecture selection is that it is a discrete, rather than continuous, control of the complexity of the model, and therefore can be a bit of a blunt instrument, especially when the ideal complexity is low.
However, this is all subject to the "no free lunch" theorems, while regularisation is effective in most cases, there will always be cases where architecture selection works better, and the only way to find out if that is true of the problem at hand is to try both approaches and cross-validate.
If I were to build an automated neural network builder, I would use Radford Neal's Hybrid Monte Carlo (HMC) sampling-based Bayesian approach, and use a large network and integrate over the weights rather than optimise the weights of a single network. However that is computationally expensive and a bit of a "black art", but the results Prof. Neal achieves suggests it is worth it! | How to choose the number of hidden layers and nodes in a feedforward neural network?
I am working on an empirical study of this at the moment (approching a processor-century of simulations on our HPC facility!). My advice would be to use a "large" network and regularisation, if you u |
32 | How to choose the number of hidden layers and nodes in a feedforward neural network? | • Number of hidden nodes: There is no magic formula for selecting the optimum number of hidden neurons. However, some thumb rules are available for calculating the number of hidden neurons. A rough approximation can be obtained by the geometric pyramid rule proposed by Masters (1993). For a three layer network with n input and m output neurons, the hidden layer would have $\sqrt{n*m}$ neurons.
Ref:
1 Masters, Timothy. Practical neural network recipes in C++. Morgan Kaufmann, 1993.
[2] http://www.iitbhu.ac.in/faculty/min/rajesh-rai/NMEICT-Slope/lecture/c14/l1.html | How to choose the number of hidden layers and nodes in a feedforward neural network? | • Number of hidden nodes: There is no magic formula for selecting the optimum number of hidden neurons. However, some thumb rules are available for calculating the number of hidden neurons. A rough ap | How to choose the number of hidden layers and nodes in a feedforward neural network?
• Number of hidden nodes: There is no magic formula for selecting the optimum number of hidden neurons. However, some thumb rules are available for calculating the number of hidden neurons. A rough approximation can be obtained by the geometric pyramid rule proposed by Masters (1993). For a three layer network with n input and m output neurons, the hidden layer would have $\sqrt{n*m}$ neurons.
Ref:
1 Masters, Timothy. Practical neural network recipes in C++. Morgan Kaufmann, 1993.
[2] http://www.iitbhu.ac.in/faculty/min/rajesh-rai/NMEICT-Slope/lecture/c14/l1.html | How to choose the number of hidden layers and nodes in a feedforward neural network?
• Number of hidden nodes: There is no magic formula for selecting the optimum number of hidden neurons. However, some thumb rules are available for calculating the number of hidden neurons. A rough ap |
33 | How to choose the number of hidden layers and nodes in a feedforward neural network? | As far as I know there is no way to select automatically the number of layers and neurons in each layer. But there are networks that can build automatically their topology, like EANN (Evolutionary Artificial Neural Networks, which use Genetic Algorithms to evolved the topology).
There are several approaches, a more or less modern one that seemed to give good results was NEAT (Neuro Evolution of Augmented Topologies). | How to choose the number of hidden layers and nodes in a feedforward neural network? | As far as I know there is no way to select automatically the number of layers and neurons in each layer. But there are networks that can build automatically their topology, like EANN (Evolutionary Art | How to choose the number of hidden layers and nodes in a feedforward neural network?
As far as I know there is no way to select automatically the number of layers and neurons in each layer. But there are networks that can build automatically their topology, like EANN (Evolutionary Artificial Neural Networks, which use Genetic Algorithms to evolved the topology).
There are several approaches, a more or less modern one that seemed to give good results was NEAT (Neuro Evolution of Augmented Topologies). | How to choose the number of hidden layers and nodes in a feedforward neural network?
As far as I know there is no way to select automatically the number of layers and neurons in each layer. But there are networks that can build automatically their topology, like EANN (Evolutionary Art |
34 | How to choose the number of hidden layers and nodes in a feedforward neural network? | I've listed many ways of topology learning in my masters thesis, chapter 3. The big categories are:
Growing approaches
Pruning approaches
Genetic approaches
Reinforcement Learning
Convolutional Neural Fabrics | How to choose the number of hidden layers and nodes in a feedforward neural network? | I've listed many ways of topology learning in my masters thesis, chapter 3. The big categories are:
Growing approaches
Pruning approaches
Genetic approaches
Reinforcement Learning
Convolutional Neura | How to choose the number of hidden layers and nodes in a feedforward neural network?
I've listed many ways of topology learning in my masters thesis, chapter 3. The big categories are:
Growing approaches
Pruning approaches
Genetic approaches
Reinforcement Learning
Convolutional Neural Fabrics | How to choose the number of hidden layers and nodes in a feedforward neural network?
I've listed many ways of topology learning in my masters thesis, chapter 3. The big categories are:
Growing approaches
Pruning approaches
Genetic approaches
Reinforcement Learning
Convolutional Neura |
35 | How to choose the number of hidden layers and nodes in a feedforward neural network? | Automated ways of building neural networks using global hyper-parameter search:
Input and output layers are fixed size.
What can vary:
the number of layers
number of neurons in each layer
the type of layer
Multiple methods can be used for this discrete optimization problem, with the network out of sample error as the cost function.
1) Grid / random search over the parameter space, to start from a slightly better position
2) Plenty of methods that could be used for finding the optimal architecture. (Yes, it takes time).
3) Do some regularization, rinse, repeat. | How to choose the number of hidden layers and nodes in a feedforward neural network? | Automated ways of building neural networks using global hyper-parameter search:
Input and output layers are fixed size.
What can vary:
the number of layers
number of neurons in each layer
the type | How to choose the number of hidden layers and nodes in a feedforward neural network?
Automated ways of building neural networks using global hyper-parameter search:
Input and output layers are fixed size.
What can vary:
the number of layers
number of neurons in each layer
the type of layer
Multiple methods can be used for this discrete optimization problem, with the network out of sample error as the cost function.
1) Grid / random search over the parameter space, to start from a slightly better position
2) Plenty of methods that could be used for finding the optimal architecture. (Yes, it takes time).
3) Do some regularization, rinse, repeat. | How to choose the number of hidden layers and nodes in a feedforward neural network?
Automated ways of building neural networks using global hyper-parameter search:
Input and output layers are fixed size.
What can vary:
the number of layers
number of neurons in each layer
the type |
36 | How to choose the number of hidden layers and nodes in a feedforward neural network? | Sorry I can't post a comment yet so please bear with me. Anyway, I bumped into this discussion thread which reminded me of a paper I had seen very recently. I think it might be of interest to folks participating here:
AdaNet: Adaptive Structural Learning of Artificial Neural Networks
Corinna Cortes, Xavier Gonzalvo, Vitaly Kuznetsov, Mehryar Mohri,
Scott Yang ; Proceedings of the 34th International Conference on
Machine Learning, PMLR 70:874-883, 2017.
Abstract We present a new framework for analyzing and learning
artificial neural networks. Our approach simultaneously and adaptively
learns both the structure of the network as well as its weights. The
methodology is based upon and accompanied by strong data-dependent
theoretical learning guarantees, so that the final network
architecture provably adapts to the complexity of any given problem. | How to choose the number of hidden layers and nodes in a feedforward neural network? | Sorry I can't post a comment yet so please bear with me. Anyway, I bumped into this discussion thread which reminded me of a paper I had seen very recently. I think it might be of interest to folks pa | How to choose the number of hidden layers and nodes in a feedforward neural network?
Sorry I can't post a comment yet so please bear with me. Anyway, I bumped into this discussion thread which reminded me of a paper I had seen very recently. I think it might be of interest to folks participating here:
AdaNet: Adaptive Structural Learning of Artificial Neural Networks
Corinna Cortes, Xavier Gonzalvo, Vitaly Kuznetsov, Mehryar Mohri,
Scott Yang ; Proceedings of the 34th International Conference on
Machine Learning, PMLR 70:874-883, 2017.
Abstract We present a new framework for analyzing and learning
artificial neural networks. Our approach simultaneously and adaptively
learns both the structure of the network as well as its weights. The
methodology is based upon and accompanied by strong data-dependent
theoretical learning guarantees, so that the final network
architecture provably adapts to the complexity of any given problem. | How to choose the number of hidden layers and nodes in a feedforward neural network?
Sorry I can't post a comment yet so please bear with me. Anyway, I bumped into this discussion thread which reminded me of a paper I had seen very recently. I think it might be of interest to folks pa |
37 | How to choose the number of hidden layers and nodes in a feedforward neural network? | I'd like to suggest a less common but super effective method.
Basically, you can leverage a set of algorithms called "genetic algorithms" that try a small subset of the potential options (random number of layers and nodes per layer). It then treats this population of options as "parents" that create children by combining/ mutating one or more of the parents much like organisms evolve. The best children and some random ok children are kept in each generation and over generations, the fittest survive.
For ~100 or fewer parameters (such as the choice of the number of layers, types of layers, and the number of neurons per layer), this method is super effective. Use it by creating a number of potential network architectures for each generation and training them partially till the learning curve can be estimated (100-10k mini-batches typically depending on many parameters). After a few generations, you may want to consider the point in which the train and validation start to have significantly different error rate (overfitting) as your objective function for choosing children. It may be a good idea to use a very small subset of your data (10-20%) until you choose a final model to reach a conclusion faster. Also, use a single seed for your network initialization to properly compare the results.
10-50 generations should yield great results for a decent sized network. | How to choose the number of hidden layers and nodes in a feedforward neural network? | I'd like to suggest a less common but super effective method.
Basically, you can leverage a set of algorithms called "genetic algorithms" that try a small subset of the potential options (random numbe | How to choose the number of hidden layers and nodes in a feedforward neural network?
I'd like to suggest a less common but super effective method.
Basically, you can leverage a set of algorithms called "genetic algorithms" that try a small subset of the potential options (random number of layers and nodes per layer). It then treats this population of options as "parents" that create children by combining/ mutating one or more of the parents much like organisms evolve. The best children and some random ok children are kept in each generation and over generations, the fittest survive.
For ~100 or fewer parameters (such as the choice of the number of layers, types of layers, and the number of neurons per layer), this method is super effective. Use it by creating a number of potential network architectures for each generation and training them partially till the learning curve can be estimated (100-10k mini-batches typically depending on many parameters). After a few generations, you may want to consider the point in which the train and validation start to have significantly different error rate (overfitting) as your objective function for choosing children. It may be a good idea to use a very small subset of your data (10-20%) until you choose a final model to reach a conclusion faster. Also, use a single seed for your network initialization to properly compare the results.
10-50 generations should yield great results for a decent sized network. | How to choose the number of hidden layers and nodes in a feedforward neural network?
I'd like to suggest a less common but super effective method.
Basically, you can leverage a set of algorithms called "genetic algorithms" that try a small subset of the potential options (random numbe |
38 | How to choose the number of hidden layers and nodes in a feedforward neural network? | Number of Hidden Layers and what they can achieve:
0 - Only capable of representing linear separable functions or decisions.
1 - Can approximate any function that contains a continuous mapping from one finite space to another.
2 - Can represent an arbitrary decision boundary to arbitrary accuracy with rational activation functions and can approximate any
smooth mapping to any accuracy.
More than 2 - Additional layers can learn complex representations (sort of automatic feature engineering) for layer layers. | How to choose the number of hidden layers and nodes in a feedforward neural network? | Number of Hidden Layers and what they can achieve:
0 - Only capable of representing linear separable functions or decisions.
1 - Can approximate any function that contains a continuous mapping from | How to choose the number of hidden layers and nodes in a feedforward neural network?
Number of Hidden Layers and what they can achieve:
0 - Only capable of representing linear separable functions or decisions.
1 - Can approximate any function that contains a continuous mapping from one finite space to another.
2 - Can represent an arbitrary decision boundary to arbitrary accuracy with rational activation functions and can approximate any
smooth mapping to any accuracy.
More than 2 - Additional layers can learn complex representations (sort of automatic feature engineering) for layer layers. | How to choose the number of hidden layers and nodes in a feedforward neural network?
Number of Hidden Layers and what they can achieve:
0 - Only capable of representing linear separable functions or decisions.
1 - Can approximate any function that contains a continuous mapping from |
39 | What is the difference between "likelihood" and "probability"? | The answer depends on whether you are dealing with discrete or continuous random variables. So, I will split my answer accordingly. I will assume that you want some technical details and not necessarily an explanation in plain English.
Discrete Random Variables
Suppose that you have a stochastic process that takes discrete values (e.g., outcomes of tossing a coin 10 times, number of customers who arrive at a store in 10 minutes etc). In such cases, we can calculate the probability of observing a particular set of outcomes by making suitable assumptions about the underlying stochastic process (e.g., probability of coin landing heads is $p$ and that coin tosses are independent).
Denote the observed outcomes by $O$ and the set of parameters that describe the stochastic process as $\theta$. Thus, when we speak of probability we want to calculate $P(O|\theta)$. In other words, given specific values for $\theta$, $P(O|\theta)$ is the probability that we would observe the outcomes represented by $O$.
However, when we model a real life stochastic process, we often do not know $\theta$. We simply observe $O$ and the goal then is to arrive at an estimate for $\theta$ that would be a plausible choice given the observed outcomes $O$. We know that given a value of $\theta$ the probability of observing $O$ is $P(O|\theta)$. Thus, a 'natural' estimation process is to choose that value of $\theta$ that would maximize the probability that we would actually observe $O$. In other words, we find the parameter values $\theta$ that maximize the following function:
$L(\theta|O) = P(O|\theta)$
$L(\theta|O)$ is called the likelihood function. Notice that by definition the likelihood function is conditioned on the observed $O$ and that it is a function of the unknown parameters $\theta$.
Continuous Random Variables
In the continuous case the situation is similar with one important difference. We can no longer talk about the probability that we observed $O$ given $\theta$ because in the continuous case $P(O|\theta) = 0$. Without getting into technicalities, the basic idea is as follows:
Denote the probability density function (pdf) associated with the outcomes $O$ as: $f(O|\theta)$. Thus, in the continuous case we estimate $\theta$ given observed outcomes $O$ by maximizing the following function:
$L(\theta|O) = f(O|\theta)$
In this situation, we cannot technically assert that we are finding the parameter value that maximizes the probability that we observe $O$ as we maximize the PDF associated with the observed outcomes $O$. | What is the difference between "likelihood" and "probability"? | The answer depends on whether you are dealing with discrete or continuous random variables. So, I will split my answer accordingly. I will assume that you want some technical details and not necessari | What is the difference between "likelihood" and "probability"?
The answer depends on whether you are dealing with discrete or continuous random variables. So, I will split my answer accordingly. I will assume that you want some technical details and not necessarily an explanation in plain English.
Discrete Random Variables
Suppose that you have a stochastic process that takes discrete values (e.g., outcomes of tossing a coin 10 times, number of customers who arrive at a store in 10 minutes etc). In such cases, we can calculate the probability of observing a particular set of outcomes by making suitable assumptions about the underlying stochastic process (e.g., probability of coin landing heads is $p$ and that coin tosses are independent).
Denote the observed outcomes by $O$ and the set of parameters that describe the stochastic process as $\theta$. Thus, when we speak of probability we want to calculate $P(O|\theta)$. In other words, given specific values for $\theta$, $P(O|\theta)$ is the probability that we would observe the outcomes represented by $O$.
However, when we model a real life stochastic process, we often do not know $\theta$. We simply observe $O$ and the goal then is to arrive at an estimate for $\theta$ that would be a plausible choice given the observed outcomes $O$. We know that given a value of $\theta$ the probability of observing $O$ is $P(O|\theta)$. Thus, a 'natural' estimation process is to choose that value of $\theta$ that would maximize the probability that we would actually observe $O$. In other words, we find the parameter values $\theta$ that maximize the following function:
$L(\theta|O) = P(O|\theta)$
$L(\theta|O)$ is called the likelihood function. Notice that by definition the likelihood function is conditioned on the observed $O$ and that it is a function of the unknown parameters $\theta$.
Continuous Random Variables
In the continuous case the situation is similar with one important difference. We can no longer talk about the probability that we observed $O$ given $\theta$ because in the continuous case $P(O|\theta) = 0$. Without getting into technicalities, the basic idea is as follows:
Denote the probability density function (pdf) associated with the outcomes $O$ as: $f(O|\theta)$. Thus, in the continuous case we estimate $\theta$ given observed outcomes $O$ by maximizing the following function:
$L(\theta|O) = f(O|\theta)$
In this situation, we cannot technically assert that we are finding the parameter value that maximizes the probability that we observe $O$ as we maximize the PDF associated with the observed outcomes $O$. | What is the difference between "likelihood" and "probability"?
The answer depends on whether you are dealing with discrete or continuous random variables. So, I will split my answer accordingly. I will assume that you want some technical details and not necessari |
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